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3 years ago

High speed wind current is called

Physics

2 answers:

rusak2 [61]3 years ago

6 0

High speed wind current is called ocean current

OLga [1]3 years ago

3 0

Ocean current is the other name for it

You might be interested in

Which of the following is an example in which you are traveling at constant speed but not at constant velocity?

grin007 [14]

Answer:

c) Driving around in a circle at exactly 100 km/hr.

This examples represents constant speed but not constant velocity.

Explanation:

To answer this question it is importan to know the difference between the concept of speed and velocity.

speed: Is the ratio of change in the displacement per unit of time. JUST A MAGNITUDE

velocity: Is the ratio of change in the displacement per unit of time in a given direction. It is a composed value by magnitude and direction, this is know as a VECTOR.

So, in conclusion the speed is the magnitude or the scalar value, for the velocity vector.

In the example,

in a) Rolling freely down a hill in a cart, traveling in a straight line. There is a component of acceleration, from earth gravity, so the speed is changing.

in b) Driving backward at exactly 50 km/hr. The direction and speed are the same, so speed and velocity are constant.

In d) Jumping up and down, with a period of exactly 60 hops per minute. There are changes in the speed, due to the acceleration and decceleration between the changes in the direction. Actually you have to stop to change direction between the ups and downs in the jumps. Also there is the gravitational component, always changing the speed.

In c) Driving around in a circle at exactly 100 km/hr. In this case the speed remains constant, while the direction is changing all the time.

3 0

4 years ago

"KATZPSEF1 7.P.053.MI. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER Two black holes (the remains of exploded stars), separated by

eduard

Answer:

There are two possible solutions.

M1 = 4.68*10^30kg, M2 = 5.53*10^30kg

M1 = 5.53*10^30kg, M2 = 4.7*10^29kg

Explanation:

In order to find the mass of each black hole, you take into account the gravitational force between them and the sum of their masses.

You use the formula for the gravitational force between two masses:

$F_g=G\frac{M_1M_2}{r^2}$ (1)

G: Cavendish's constant = 6.674*10^-11 m^3/kg.s^2

M1, M2: mass of each black hole = ?

r: distance between the black holes = 10.0 AU = 10.0(1.50*10^11m) = 1.5*10^12m

Fg: gravitational force between the black holes = 7.70*10^25N

Furthermore, you take into account that the sum of the masses M1 and M2 is:

M1 + M2 = 6.00*10^30 kg (2)

You solve the equation (2) for M2.

$M_2=6.00*10^{30}-M_1$

Next, you replace the obtained expression for M2 into the equation (1) and solve for M1, as follow (for simplicity, you do not add the units):

$F_g=G\frac{M_1(6.00*10^{30}-M_1)}{r^2}\\\\\frac{r^2F_g}{G}=6.00*10^{30}M_1-M_1^2\\\\\frac{(1.5*10^{12})^2(7.70*10^{25})}{(6.674*10^{-11}}=6.00*10^{30}M_1-M_1^2\\\\2.59*10^{60}=6.00*10^{30}M_1-M_1^2\\\\M_1^2-6.00*10^{30}M_1+2.59*10^{60}=0$

Then, you have obtained a quadratic polynomial. You solve it with the quadratic formula:

$M_1=\frac{-(-6.00*10^{30})\pm \sqrt{(-6.00*10^{30})^2-4(1)(2.59*10^{60}))}}{2(1)}\\\\M_1=\frac{6.00*10^{30}\pm 5.06*10^{30}}{2}\\\\M_1=4.68*10^{29}\\\\M_1=5.53*10^{30}$

Both results are consistent, then the mass of one black hole can be 4.68*10^30kg and also 5.53*10^30kg.

The other black hole has a mass of:

$M_2=6.00*10^{30}kg-4.68*10^{29}kg=5.53*10^{30}kg\\\\M_2=6.00*10^{30}kg-5.53*10^{30}kg=4.7*10^{29}kg$

Hence, you have a pair of solutions:

M1 = 4.68*10^30kg, M2 = 5.53*10^30kg

M1 = 5.53*10^30kg, M2 = 4.7*10^29kg

3 0

3 years ago

(b) Can the speed of a rocket exceed the exhaust speed of the fuel? Explain.

muminat

Yes. The speed of a rocket can exceed the exhaust speed of the fuel.

How this is explained?

The thrust of the rocket does not depend on the relative speed of the gases or the relative speed of the rocket.
It depends on conservation of momentum.

What is conservation of momentum?

Conservation of momentum, general law of physics according to which the quantity called momentum that characterizes motion never changes in an isolated collection of objects; that is, the total momentum of a system remains constant.

Momentum is equal to the mass of an object multiplied by its velocity and is equivalent to the force required to bring the object to a stop in a unit length of time.
For any array of several objects, the total momentum is the sum of the individual momenta.
There is a peculiarity, however, in that momentum is a vector, involving both the direction and the magnitude of motion, so that the momenta of objects going in opposite directions can cancel to yield an overall sum of zero.

To know more about conservation of momentum, refer:

brainly.com/question/7538238

#SPJ4

4 0

2 years ago

Discuss Joule-Thompson effect with relevant examples and formulae.

Delicious77 [7]

Answer:

$\mu _j=\dfrac{1}{C_p}\left [T\left(\frac{\partial v}{\partial T}\right)_p-v\right]dp$

Explanation:

Joule -Thompson effect

Throttling phenomenon is called Joule -Thompson effect.We know that throttling is a process in which pressure energy will convert in to thermal energy.

Generally in throttling exit pressure is low as compare to inlet pressure but exit temperature maybe more or less or maybe remains constant depending upon flow or fluid flow through passes.

Now lets take Steady flow process

Let

$P_1,T_1$ Pressure and temperature at inlet and