Answer:
Explanation:
We shall represent all the forces in vector form .
Force of 95 pounds
F₁ = 95cos100 i + 95sin100j
= -16.5 i +93.55 j
force of 75 pounds
F₂ = 75cos200 + 75sin200j
= -70.47 i - 25.65 j
force of 146 pounds
F₃ = 146cos300 i + 146sin300j
= 73i -126.44 j
Resultant force
R = F₁+ F₂ + F₃
= -16.5 i +93.55 j -70.47 i - 25.65 j +73i -126.44 j
= -13.97 i - 58.54 j
Magnitude of R = √ ( 13.97² + 58.54² )
= 60.18
If Ф be angle of resultant with axis
tanФ = - 58.54 / -13.97
Ф = 76.57 + 180 = 256.57 , because both x and y components are negative. So the resultant will be in third quadrant.
Answer:
I = PRT
18 = 150(R)(2)
18 = 300R
R = 0.06
So A is correct.
Let me know if this helps!
