Answer:
Distance covered to top of the hill was : 1.755 km
Explanation:
Initial velocity = 35 km/hr
Acceleration = 2.0 km/hr²
Time taken to accelerate = 3 minutes = 3/60 hours = 1/20 hours
Formula for acceleration : a = Δv /t
v-u/t ---where u is initial velocity , v is final velocity and t is time taken for acceleration
v- 35 / 0.05 = 2
v = 35.10 km/h
Formula for distance is product of speed and time
Distance covered = 35.10 * 0.05 = 1.755 km
Answer:
The current through the inductor at the end of 2.60s is 9.7 mA.
Explanation:
Given;
emf of the inductor, V = 41.0 mV
inductance of the inductor, L = 13 H
initial current in the inductor, I₀ = 1.5 mA
change in time, Δt = 2.6 s
The emf of the inductor is given by;

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.
Answer:
2.48 m/s
Explanation:
We can use the kinematic equation,
s = ut +½at²
Where
s = displacement
u = initial velocity
t = time taken
a = acceleration
Using the equation in vertical direction,
321 = 0×t +½×g×t², u = 0 because initial vertical velocity is 0
We get t = 8.01 s
Using the equation in the horizontal direction,
52 = u×8.01 +½×0×(8.01)²,. a = 0 because no unbalanced force act on object in that direction
So u = 2.48 m/s
Answer:
The magnitude of the electric force on a protein with this charge is 
Explanation:
Given that,
Electric field = 1500 N/C
Charge = 30 e
We need to calculate the magnitude of the electric force on a protein with this charge
Using formula of electrostatic force

Where, F = force
E = electric field
q = charge
Put the value into the formula


Hence, The magnitude of the electric force on a protein with this charge is 