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Rufina [12.5K]
3 years ago
13

A worker pushes horizontally on a large crate with force of 298 N and the crate is moved 4.3 m. How much work was done?

Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

1281.4 J

Explanation:

F = 298 N

d = 4.3 m

the work done is defined as the product of force applied in the direction of displacement and the displacement.

W = force x displacement

Work is a scalar quantity and its SI unit is Joule.

W = F x d

W = 298 x 4.3 = 1281.4 J

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If gravity had no effect on a ball after you threw it ... and there also
were no air to slow it down ... then the ball would continue traveling
in a straight line, in whatever direction you threw it. 

That's the heart and soul of Newton's laws of motion ... any object
keeps moving at the same speed, and in a straight line in the same
direction, until a force acts on it to change its speed or direction.\

If you threw the ball horizontally, then it would keep moving in the
same direction you threw it.  But don't forget:  The Earth is not flat.
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3 years ago
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I need question 5 please and correct any others if they’re wrong
Kryger [21]
The resistance would increase.
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3 years ago
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Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 167 cm , but its circumference is decreasi
PSYCHO15rus [73]

Answer:

a)     fem = - 0.0103 V,  b) the applied field is in a vertical upward direction, the induced current is clockwise.

Explanation:

a) For this exercise we use Faraday's law

         fem =  - \frac{d \phi}{dty}

   

the magnetic flux is

         Ф = B. A = B A cos θ

The bold letters indicate vectors, in this case the direction of the magnetic field and the normal to the circumference is parallel therefore the angle is zero and the cos 0 = 1

         fem = - B dA / dt

the area of ​​a circle is

        A = π r²

l

et's perform the derivative

         dA / dt =π 2r \frac{dr}{dt}

we substitute

          fem = - B 2π r \frac{dr}{dt}

the circumference of a circle is

         L = 2π r

we substitute

          fem = - B L  ( L  )

          fem =  

Let's find the circumference for the 9 s, let's use a direct rule of proportions

If the circumference changes 13cm at t = 1. how much does it change at t=9s

         ΔL = 13cm (9s / 1s) = 117cm

the circumference that is

        L = Lo - ΔL

        L = 167 - 117

        L = 50 cm

let's reduce all magnitudes to the SI system

         L = 0.50 m

          = 0.130 m / s

calculate us

         fem = - 1.00 0.50 0.130

         fem = - 0.0103 V

b) the electromotive force induced in the opposite direction to the change of the radius and is decreasing with time, the current follows the direction of the decreased voltage therefore the current is induced in the opposite direction to the change of the magnetic flux.

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3 0
3 years ago
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Answer:

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madreJ [45]

Answer:

0.916v_{ex}

Explanation:

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v = v_{ex} ln(\frac{m_{o}}{0.4m_{o}}) = v_{ex}*ln(2.5) = v_{ex}*0.916 = 0.916v_{ex}

Therefore, the maximum speed of the rocket is 0.916v_{ex}

8 0
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