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3 years ago

A worker pushes horizontally on a large crate with force of 298 N and the crate is moved 4.3 m. How much work was done?

Physics

1 answer:

Katyanochek1 [597]3 years ago

5 0

Answer:

1281.4 J

Explanation:

F = 298 N

d = 4.3 m

the work done is defined as the product of force applied in the direction of displacement and the displacement.

W = force x displacement

Work is a scalar quantity and its SI unit is Joule.

W = F x d

W = 298 x 4.3 = 1281.4 J

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What is Newton’s first law

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Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.

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Stephanie serves a volleyball from a height of 0.80 m and gives it an initial velocity of +7.2 m/s straight up. how high will th

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3 years ago

• ¿Qué rapidez tendrá un sonido de 150 Hz con una longitud de onda de 2 metros?

kobusy [5.1K]

Answer:

Speed = 300 m/s

Explanation:

Given the following data;

Frequency = 150 Hz

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To find the speed of the wave;

Mathematically, the speed of a wave is given by the formula:

$Speed = wavelength * frequency$

Substituting into the formula, we have;

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3 years ago

A 10 kg migratory swan cruises at 20m/s. A calculation that takes into ac-count the necessary forces shows that this motion requ

IgorC [24]

Answer:

Part A:

Distance=864000 m=864 km

Part B:

Energy Used=ΔE=8638000 Joules

Part C:

$\frac{\triangle m}{m}=0.004998=0.49985\%$

Explanation:

Given Data:

v=20m/s

Time =t=12 hours

In Secs:

Time=12*60*60=43200 secs

Solution:

Part A:

Distance = Speed**Time

Distance=v*t

Distance= 20*43200

Distance=864000 m=864 km

Part B:

Energy Used=ΔE= Energy Required-Kinetic Energy of swans

Energy Required to move= Power Required*time

Energy Required to move=200*43200=8640000 Joules

Kinetic Energy= $\frac{1}{2}mv^2$

$K.E\ of\ Swans=\frac{1}{2} *10*(20)^2=2000\ Joules$

Energy Used=ΔE=8640000 -2000

Energy Used=ΔE=8638000 Joules

Part C:

Fraction of Mass used=Δm/m

For This first calculate fraction of energy used:

Fraction of energy=ΔE/Energy required to move

ΔE is calculated in part B

Fraction of energy=8638000/8640000

Fraction of energy=0.99977

Kinetic Energy= $\frac{1}{2}mv^2$

Now, the relation between energies ratio and masses is:

$\frac{\triangle E}{E}=\frac{\triangle m}{2m}v^2$

$\frac{\triangle m}{m}=\frac{2}{v^2} *\frac{\triangle E}{E}\\\frac{\triangle m}{m}=\frac{2}{20^2} *0.99977$

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3 years ago

The main strength and weakness of traditional economy?

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