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Rufina [12.5K]
3 years ago
13

A worker pushes horizontally on a large crate with force of 298 N and the crate is moved 4.3 m. How much work was done?

Physics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Answer:

1281.4 J

Explanation:

F = 298 N

d = 4.3 m

the work done is defined as the product of force applied in the direction of displacement and the displacement.

W = force x displacement

Work is a scalar quantity and its SI unit is Joule.

W = F x d

W = 298 x 4.3 = 1281.4 J

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The voltage leaving the secondary coil of a transformer is equal to 240 V. The secondary coil is wrapped 8 times around the core
Lina20 [59]

The initial voltage at the primary= 750 V

Explanation:

for a transformer

Es/ Ep= Ns/ Np

Es= secondary voltage= 240 V

Ep= primary voltage

Ns= number of turns in the secondary=8

Np= Number of turns in the primary=25

so 240/Ep=8/25

Ep=750 V

7 0
3 years ago
Read 2 more answers
A standard steel pipe (D = 3.81 in.; d = 3.24 in.) supports a concentrated load of P = 930 lb. The span length of the cantilever
Maurinko [17]

Answer:

a) τmax = 586.78 P.S.I.

b) σmax = 15942.23 P.S.I

Explanation:

D = 3.81 in

d = 3.24 in

P = 930 lb

L = 3.7 ft = 44.4 in

a) The maximum horizontal shear stress can be obtained as follows

τ = V*Q / (t*I)

where

V = P = 930 lb

Q = (2/3)*(R³- r³) = (1/12)*(D³- d³) = (1/12)*((3.81 in)³- (3.24 in)³)

⇒ Q = 1.7745 in³

t = D - d = 3.81 in - 3.24 in = 0.57 in

I = (π/64)*(D⁴-d⁴) = (π/64)*((3.81 in)⁴- (3.24 in)⁴) = 4.9341 in⁴

then

τ = (930 lb)*(1.7745 in³) / (0.57 in*4.9341 in⁴)

⇒ τmax = 586.78 P.S.I.

b) We can apply the following equation in order to get the maximum tension bending stress in the pipe

σmax = Mmax *y / I

where

Mmax = P*L = 930 lb*44.4 in = 41292 lb-in

y = D/2 = 3.81 in /2 = 1.905 in

I = 4.9341 in⁴

then

σmax = (41292 lb-in)*(1.905 in) / (4.9341 in⁴) = 15942.23 P.S.I

6 0
4 years ago
1. Which has more kinetic energy, a 40 kg cheetah running at 25 m/s or a 4,000 kg elephant moving at 2 m/s? How much more energy
s2008m [1.1K]

Answer:

1. The elephant has more kinetic energy at this speed and mass. It has 4,500 J more KE.

2. The elephant would have to go at a speed of 2.5 m/s to reach the same KE as the cheetah.

Explanation:

You would use the formula KE=1/2mv^2.

This formula would be filled in and completed twice, once for the elephant and once for the cheetah.

Cheetah:

KE = 1/2 (40) (25) ^2

KE = 12,500 J

Elephant:

KE = 1/2 (4,000) (2) ^2

KE = 8,000 J

This shows that the cheetah has more KE.

Then you would subtract the elephants amount of J from the cheetahs to find the difference.

Difference = 12,500 J - 8,000 J

Difference = 4,500 J

I hoped this helped with the first part :)

For the second part:

To find the speed the elephant would have to run you would fill in and complete the equation once more with different distance results.

KE = 1/2 (4,000) (2.5) ^2

KE= 12,500 J

7 0
3 years ago
How do you write a letter to the editor of a newspaper in reference to bullying
suter [353]

How do you write a letter to the editor?

Open the letter with a simple salutation. ...

Grab the reader's attention. ...

Explain what the letter is about at the start. ...

Explain why the issue is important. ...

Give evidence for any praise or criticism. ...

State your opinion about what should be done. ...

Keep it brief. ...

Sign the letter.

5 0
3 years ago
Why does an egg dropped from a higher height move faster as it reaches the ground than an egg dropped from a lower height?
nignag [31]

Answer:When an egg is dropped from a higher height, it reaches a greater speed before hitting the ground. So the egg dropped from 5 meters has a greater velocity when it strikes the ground. It thus experiences the greater velocity change during the collision.

Explanation:

8 0
3 years ago
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