The answer is b) false. Stars are mainly classified by their spectra (the elements they absorb) and their temperature.
Answer:
Angular acceleration = 0.95rad/s
Number or revolution is 13
Explanation:
See attached file
Answer:
C) The rate of change from potential to kinetic energy is exponential.
Explanation:
As we know that total mechanical energy must be conserved here
As we know that there is no friction force on this system of electromagnet and nail
So here we can say that that
Magnetic potential energy of the nail + electromagnet system will convert into kinetic energy of the nail as it is released.
So we will have
Initial potential energy = work done to move it away by 10 cm


now as the nail is released then this potential energy will start to convert into kinetic energy
So here correct answer must be
C) The rate of change from potential to kinetic energy is exponential.
Answer:
a rock of 50kg should be placed =drock=0.5m from the pivot point of see saw
Explanation:
τchild=τrock
Use the equation for torque in this equation.
(F)child(d)child)=(F)rock(d)rock)
The force of each object will be equal to the force of gravity.
(m)childg(d)child)=(m)rockg(d)rock)
Gravity can be canceled from each side of the equation. for simplicity.
(m)child(d)child)=(m)rock(d)rock)
Now we can use the mass of the rock and the mass of the child. The total length of the seesaw is two meters, and the child sits at one end. The child's distance from the center of the seesaw will be one meter.
(25kg)(1m)=(50kg)drock
Solve for the distance between the rock and the center of the seesaw.
drock=25kg⋅m50kg
drock=0.5m
Answer:

Explanation:
This work done is in the form of Potential Energy so we'll use the formula of Potential Energy.
<u>Given Data:</u>
Mass = m = 250 kg
Acceleration due to gravity = g = 9.8 m/s²
Height = h = 6 m
<u>Required:</u>
Work Done in the form of Potential Energy = P.E. = ?
<u>Formula:</u>
P.E. = mgh
<u>Solution:</u>
P.E. = (250)(9.8)(6)
P.E. = 14700 Joules
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>