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Nataly [62]
3 years ago
10

A cassette recorder uses a plug-in transformer to convert 120 V to 12.0 V, with a maximum current output of 200 mA. What is the

current input?
Physics
1 answer:
goldfiish [28.3K]3 years ago
4 0

Answer:

20 mA

Explanation:

We have given that the transformer convert 120 V to 12 V means it is a step down transformer

The turn ratio of the transformer is given as a=\frac{N_1}{N_2}=\frac{V_1}{V_2}=\frac{120}{12}=10 here V_! is primary voltage and V_2 is secondary voltage

As the voltage decreases from primary to secondary so current will increase from primary to secondary

We have given output current that is secondary current so primary that is input current will be less

So input current =\frac{200}{10}=20mA

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Answer:

The answer is pathology

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3 years ago
50W of power is generated using 100J of work to move a box onto a shelf. How long did it take to move the box from the floor to
svetoff [14.1K]

Answer: time t = 2 seconds

Explanation:

Given that

Power P = 50W

Energy E = 100J

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Power is defined as the rate at which work is done. I.e

P = W.D/t

Where work done = energy

50 = 100/t

Make t the subject of formula

t = 100/50

t = 2 second

5 0
3 years ago
you are pushing a friend in a wagon.you push with a force of 40N. your friend and wagon together have a mass of 80kg. ignoring f
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Answer:

a= 0.5 m/s^2

Explanation:

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3 years ago
Figure 1.18 (Chapter 1) shows the Hoover Dam Bridge over
stiks02 [169]

Answer: 7.436 s

Explanation:

This situation is related to vertical motion, specifically free fall and can be modelled by the following equation:

y=y_{o}+V_{o} t+\frac{gt^{2}}{2}  

Where:

y= 0m is the final height of the object (when it makes splash)

y_{o}=271 m  is the initial height of the object

V_{o}=0 m/s  is the initial velocity of the object (it was dropped)

g=-9.8m/s^{2}  is the acceleration due gravity (directed downwards)

t is the time since the objecct is dropped until it makes splash

0=y_{o}+0+\frac{gt^{2}}{2}  

Clearing t:

t=\sqrt{\frac{-2y_{o}}{g}}  

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Finally:

t=7.436 s  

6 0
4 years ago
If the thrower takes 0.90 s to complete one revolution, starting from rest, what will be the speed of the discus at release?
Marysya12 [62]
Ω₀ = the initial angular velocity (from rest)
t = 0.9 s, time for a revolution
θ = 2π rad, the angular distance traveled

Let
α =  the angular acceleration
ω =  the final angular velocity

The angular rotation obeys the equation
(1/2)*(α rad/s²)*(0.9 s)² = (2π rad)
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The final angular velocity is
ω = (15.514 rad/s²)*(0.9 s) = 13.963 rad/s

If the thrower's arm is r meters long, the tangential velocity of release will be 
v = 13.963r m/s

Answer: 13.963 rad/s

8 0
3 years ago
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