Answer:
1 - third law
2 - second law
3 - first law
4 - third law
5 - second law
6 - first law
Explanation:
First law
In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force.
Second law
In an inertial frame of reference, the vector sum of the forces F on an object is equal to the mass m of that object multiplied by the acceleration, a of the object
F = ma.
Third law
When one body exerts a force on a second body, the second body simultaneously exerts a force equal in magnitude and opposite in direction on the first body.
The highest frequency (f) at which the source can operate is given as:
f = 55.133Hz.
<h3>What are sinusoidal waves?</h3>
The most realistic representation of how many objects in nature change state is a sine wave or sinusoidal wave.
A sine wave depicts how the intensity of a variable varies over time.
<h3>What is the calculation justifying the above result?</h3>
P = (1/2) μω²A²v
300W = 1/2 (4 X 10⁻²kg/m) ω₂ (0.05m)²v
Thus the wave speed is:
v = √(T/μ)
= √[(100N)/(4 X 10⁻²kg/m)
= 50m/s
300W = 1/2(4 X 10⁻²kg/m) ω²(0.05m)² (50m/s)
⇒ ω = 346.41 1/s
ω = 346.41 1/s
= 2πf
⇒ f = 55.133Hz
Learn more about Sinusoidal waves:
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Answer:
The object fell from about 38.14 meters
Explanation:
We can use the formula for displacement under accelerated motion due to gravity to find the velocity of the object had 30 m before hitting the ground :

Now, knowing this velocity, we can find the time it took to fall from the initial position to 30 m before hitting the ground:

And now we can find what is the total distance covered in 1.5 s plus 1.29 seconds for this free falling object:

Explanation:
t = t/v(1-v^2/c^2)
3.10- 1.03 = 1.03/v(1-v^2/c^2)
2.07 = 1.03/v(1-v^2/c^2)
v(1-v^2/c^2) = 0.49
squaring both sides
(1-v^2/c^2) = 0.24
0.76 = v^2/c^2
v^2 = 0.76 × (3×10^8)^2
v = 0.873×10^8
v = 2.61×10^8 m/s
s = vt
t = 3.10 years = 3.10×365×24×3600 seconds = 9.7×10^8
s = 2.61×10^8× 9.7×10^8
s = 25.31×10^16 m