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Zanzabum
3 years ago
10

A student makes a model of the sun-Earth system by swinging a ball around her head. Using this model, the student is trying to e

xplain how Earth stays on a path around the sun. ​The student explains that this path is the result of: A.the magnetic attraction between Earth and the sun. B.potential energy stored in Earth that originated in the sun. C.the gravitational attraction between the sun and Earth. D.electromagnetic energy from the sun pulling on the Earth.
Physics
2 answers:
DedPeter [7]3 years ago
8 0

Answer:

c. gravitational attraction between the sun and earth

GREYUIT [131]3 years ago
8 0

The gravitational attraction between the Sun and the Earth is exactly modeled by the tension in the string.  <em>(C)</em>

This is an excellent demonstration !  It shows:

-- If she uses a heavier ball (more mass), she gets more tension in the string, just like planets.

-- If she wants the ball (planet) to revolve faster, she has to increase the tension in the string.

-- If she lets out a longer string, the ball moves slower, and there's less tension in the string, just like planets.

-- The ball stays in the same plane all the way around, just like planets.

You might be interested in
Light enters water from air at an angle of 25° with the normal, Θ1. If water has an index of refraction of 1.33, determine Θ2.
vladimir1956 [14]
By Snell's law:

η = sini / sinr.        i = 25,  η = 1.33

1.33 = sin25° / sinr

sinr = sin25° / 1.33 = 0.4226/1.33 = 0.3177    Use a calculator.

r = sin⁻¹(0.3177)

r ≈ 18.52°

Option A.

God's grace.
6 0
3 years ago
Two point charges, with charge magnitudes q and ????, are placed a distance r apart. In this arrangement, each point charge expe
sammy [17]

Answer:

1)  Q ’= 8 Q ,  2)    q ’= 16 q ,  3)   r ’= ¾ r

Explanation:

For this exercise we will use Coulomb's law

      F = k q Q / r²

It asks us to calculate the change of any of the parameters so that the force is always F

Original values

                q, Q, r

Scenario 1

      q ’= 2q

       r ’= 4r

     F = k q ’Q’ / r’²

we substitute

     F = k 2q Q ’/ (4r)²

     F = k 2q Q '/ 16r²

we substitute the value of F

      k q Q / r² = k q Q '/ 8r²

       Q ’= 8 Q

Scenario 2

       Q ’= Q

       r ’= 4r

we substitute

      F = k q ’Q / 16r²

      k q Q / r² = k q’ Q / 16 r²

      q ’= 16 q

Scenario 3

      q ’= 3/2 q

      Q ’= ⅜ Q

we substitute

        k q Q r² = k (3/2 q) (⅜ Q) / r’²

        r’² = 9/16 r²

        r ’= ¾ r

6 0
3 years ago
Weightlessness is experienced by an astronaut in space. This means that the astronaut's muscles have to be stronger to move his
just olya [345]
The answer is false. The speed of the astronaut cancels out the force of gravity, causing a 'stationary freefall'. While under these effects, it is not required for an astronaut to 'strengthen' his body.
4 0
3 years ago
Read 2 more answers
Gravity is a force. <br> True <br> False
Ratling [72]
The answer is true. Gravity is the force that keeps us all on the ground.
7 0
3 years ago
Read 2 more answers
A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular
NeTakaya
Answer:
387 volts

Explanation:
Ohm's law is used to relate voltage, current and resistance.
The formula is as follows:V = I * R
where:
V is the applied voltage (measured in volts)
I is the current flowing (measured in amperes)
R is the resistance (measured in ohm)

In the given, we have:
current (I) = 9 amperes
resistance (R) = 43 ohm

Substitute with the givens in the above formula to get the voltage as follows:
V = 9 * 43
V = 387 volts

Hope this helps :)
4 0
3 years ago
Read 2 more answers
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