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3 years ago

What is the interquartile range for team b?

Mathematics

1 answer:

mestny [16]3 years ago

6 0

I think team red maybe

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PLZ

g100num [7]

Answer:

21 pairs of socks

Step-by-step explanation:

We can find out how much money Chang has to spend on socks by subtracting the price of sneakers from his total money to spend by solving 160 - 95. From that, we get our answer of $65 that Chang has to spend on socks. We can divide 65 by 3 to see how many pairs of socks he can buy and we get our answer of 21 pairs of socks.

(sorry if it's confusing but I hope it helped anyway)

8 0

3 years ago

Read 2 more answers

Expand the brackets 3(12-W)

3241004551 [841]

Answer:

$36 - 3m$

Step-by-step explanation:

$3(12−m)$

$3 \times 12+3(−m)$

$36+3(−m)$

$36−3m$

<h3>Hope it is helpful...</h3>

8 0

3 years ago

If 3x-1=11, then 2x=?

choli [55]

7 0

3 years ago

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.