Fnet=mass x acceleration
=650 x 4
=2600N
Answer:
A. 1.8x10⁵
Explanation:
For this question we have
72km/h = speed
Total mass = 2250kg
Stopped at t = 0.2250s
To get average force acting on this car on collision:
72km/3.6 = 20m|s
Impulse = ∆p
This implies:
F∆t = m∆v
F = m∆v/∆t
= 2250x20/0.250
= 180000
= 1.8x10⁵
Therefore option A is correct.
Answer:
b
Explanation:
it loses energy due to friction because if it hits objects the objects slow it down and which causes it to start slowing down
Shield volcanos have the most predictable eruptions.
Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
