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lys-0071 [83]
3 years ago
14

Identify the equation used to calculate the perpendicular force (F⊥) acting on a block on an inclined plane.

Physics
2 answers:
jekas [21]3 years ago
8 0

F=mg

The force of gravity is the force with which the earth or other massively large object attracts another object towards itself. This is the weight of the object. All objects upon earth experience a force of gravity that is directed "downward" towards the center of the earth. The force of gravity on earth is always equal to the weight of the object as found by the equation F=mg.

i just did it on usa testprep

pychu [463]3 years ago
6 0
Using geometrical arguments, we can see that the angle of the inclined plane \theta is equal to the angle between Fg and the perpendicular force.

But the perpendicular force is the projection of Fg along the perpendicular axis, and Fg=mg, so the correct answer is
<span>C) F=mg cosΘ </span>
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A 650 kg car accelerates at 4.0 m/s2 south. what is the net force acting on it?
Lelu [443]
Fnet=mass x acceleration 
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4 years ago
A car having a total mass of 2250 kg and traveling at 72.0 km/h smashes into a tree. The car is stopped in 0.250 s. The average
musickatia [10]

Answer:

A. 1.8x10⁵

Explanation:

For this question we have

72km/h = speed

Total mass = 2250kg

Stopped at t = 0.2250s

To get average force acting on this car on collision:

72km/3.6 = 20m|s

Impulse = ∆p

This implies:

F∆t = m∆v

F = m∆v/∆t

= 2250x20/0.250

= 180000

= 1.8x10⁵

Therefore option A is correct.

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A super ball stops bouncing because A) gravity never lets it bounce. B) it loses energy due to friction. C) it cannot gain poten
AlexFokin [52]

Answer:

b

Explanation:

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6 0
3 years ago
Which type of volcano has more predictable eruptions?
Ludmilka [50]
Shield volcanos have the most predictable eruptions.
6 0
3 years ago
Read 2 more answers
Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m
Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

so

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0
3 years ago
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