Answer:
y = 52.44 10⁻⁶ m
Explanation:
It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other
Based on this principle we must find the angle of the first minimum of the diffraction expression
a sin θ= m λ
The first minimum occurs for m = 1
sin θ = λ / a
Now let's use trigonometry the object is a distance L = 0.205 m
tan θ = y / L
Since the angles are very small, let's approximate
tan θ = sin θ/cos θ = sin θ
sin θ = y / L
We substitute in the diffraction equation
y / L = λ / a
y = λ L / a
Let's calculate
y = 550 10⁻⁹ 0.205 / 2.15 10⁻³
y = 52.44 10⁻⁶ m
Answer:
0.01 H
Explanation:
V = 12 cos (1000t + 45)
C = 100 micro farad
Let the inductance be L .
When the current and the voltage are in the same phase so it is the condition of resonance.
So capacitive reactance = inductive reactance
Xc = XL
1/ωC = ωL
L = 1 / ω²C
By comparisonV = Vo Cos (ωt + Ф)
ω = 1000 rad/s
L = 1 / (1000 x 1000 x 100 x 10^-6)
L = 1 / 100
L = 0.01H
thus, the inductance of the inductor is 0.01 H.
Answer:
14cm
Explanation:
Mass per gram of the piece of wire;
2g of the wire is found in 1m
Since
100cm = 1m;
So;
100cm of the wire contains 2g of the wire
To provide 0.28g
Since;
2g of wire is made up of 100cm
0.28g of wire will be contained in 
= 14cm
14cm of the wire will contain 0.28g
Answer:
test 5 seemed to be the hardest for me to perceive in account i only saw three f's when there was indeed 6 it was very difficult to find the f's even going very slowly.
Explanation:
correct on edge
Answer:
Clockwise direction
Explanation:
In a case of a wire carrying a current, the right hand rule is used.
The thumb in the direction of current while the finger curl around in the direction of the magnetic field.
The right hand rule applies to a current in a straight line wire.
If the direction a wire carrying a current perpendicularly into this page, the direction of the magnetic field will be in a clockwise direction .
