Answer:
(a) μ ≈ 0.57
(b) not enough information
Explanation:
Draw a free body diagram.
There are four forces acting on block B:
- Weight force Mb g pulling down
- Normal force N pushing up
- Friction force Nμ pulling left
- Tension force T₁ pulling right
There are three forces acting on the node:
- Tension force T₁ pulling left
- Tension force T₂ pulling 35° above the horizontal
- Weight force Ma g pulling down
(a)
Sum of forces on block B in the y direction:
∑F = ma
N − Mb g = 0
N = Mb g
Sum of forces on block B in the x direction:
∑F = ma
T₁ − Nμ = 0
T₁ = Nμ
T₁ = Mb g μ
Sum of forces on the node in the y direction:
∑F = ma
T₂ sin 35° − Ma g = 0
T₂ sin 35° = Ma g
Sum of forces on the node in the x direction:
∑F = ma
T₂ cos 35° − T₁ = 0
T₂ cos 35° = T₁
T₂ cos 35° = Mb g μ
Divide the previous equation by this equation, eliminating T₂.
tan 35° = Ma g / (Mb g μ)
μ = Ma / (Mb tan 35°)
μ = 0.4 / tan 35°
μ ≈ 0.57
(b) T₂ sin 35° = Ma g = 0.4 Mb g
Without knowing the value of Mb, we cannot find the value of the tension force T₂.
Answer:
The energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
Explanation:
Hope this helps & plz mark brainiest
Kinetic energy = 1/2 x mass x velocity²
10.0km x 100 = 10000m
Kinetic energy = 1/2 x 100 x 10000²
Kinetic energy = 5000000000J
122.65 or 122 kilometers per hour
Answer:
Explanation:
Given
Length
frequency
Tension in the string
Wave speed in a string is given by
where
wavelength for this wave
and