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Virty [35]
3 years ago
10

Which of the following is the best example of a proper hypothesis?

Physics
2 answers:
kobusy [5.1K]3 years ago
8 0

Correct answer choice is :


2) If two objects are dropped at the same height, the heavier object will hit the ground first.


Explanation:


A hypothesis is a regular conditional description of the predicted connection between two or more variables under examination. A simple hypothesis is that one in which there endures a relation between two variables one is called an independent variable or reason and the other is the dependent variable or outcome. A hypothesis is a trained prediction that can be examined. You will find the purpose of a hypothesis then learn how one is formed and written.


Lera25 [3.4K]3 years ago
6 0
2 because it is something that can be tested
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How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 4.57×10−21 n
hichkok12 [17]

Answer:

891 excess electrons must be present on each sphere

Explanation:

One Charge = q1 = q

Force = F = 4.57*10^-21 N  

Other charge = q2 =q

Distance = r = 20 cm = 0.2 m  

permittivity of free space = eo =8.854×10−12 C^2/ (N.m^2)  

Using Coulomb's law,

F=[1/4pieo]q1q2/r^2

F = [1/4pieo]q^2 / r^2

q^2 =F [4pieo]r^2

q =  r*sq rt F[4pieo]

 q=0.2* sq rt[ 4.57 x 10^-21]*[4*3.1416*8.854*10^-12]

q = 1.42614*10^ -16 C

number of electrons = n = q/e=1.42614*10^ -16 /1.6*10^-19

n =891

 891 excess electrons must be present on each sphere  

5 0
3 years ago
The second-order bright fringe in a single-slit diffraction pattern is 1.35 mm from the center of the central maximum. The scree
Dafna11 [192]

Answer:

The wavelength is 754.2 nm.

Explanation:

Given that,

Diffraction pattern y= 1.35 mm

Width = 0.838 mm

Distance D= 75 cm

We need to calculate the wavelength

Using formula of diffraction pattern

y=\dfrac{m\lambda D}{d}

\lambda=\dfrac{yd}{mD}

Where, y = diffraction pattern

m = order

d = width

D = distance

Put the value into the formula

\lambda=\dfrac{1.35\times10^{-3}\times0.838\times10^{-3}}{2\times75\times10^{-2}}

\lambda=7.542\times10^{-7}\ m

\lambda=754.2\ nm

Hence, The wavelength is 754.2 nm.

4 0
3 years ago
How much energy has 4×10^10m^3 of water collected in a reservoir at a hight of 100 m from the power house ?What kind of energy i
sveticcg [70]

Answer:

PE = 3.92x10^16J

potential energy

Explanation:

PE = m*g*h

mass of water = 1000kg/m³

(4*10^10m³)*1000kg = 4*10^13kg

PE = (4*10^13kg)*(9.81m/s²)*(100m)

PE = 3.92x10^16J

7 0
3 years ago
What can you conclude about this product?
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What’s the question
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