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3 years ago

8

The expression [(-7) ³ - (-7³)] - [(-7) ² + 7²] results in

2 answers:

scZoUnD [109]3 years ago

5 0

$BASIC \: \: ALGEBRA \\ \\ \\ Given \: \: expression \: - \\ ( {( - 7)}^{3} - ( { - 7)}^{3} ) - ( {( - 7)}^{2} + {(7)}^{2} ) \\ \\ = \: \: 0 \: - \: ( {( - 7)}^{2} + {(7)}^{2} ) \\ \\ = \: \: 0 \: - (49 + 49) \\ \\ = \: \: 0 - 98 \\ \\ \\ = \: \: - 98 \: \: \: \: \: \: \: \: \: \: Ans.$

Reil [10]3 years ago

4 0

[(-7)(-7)(-7) + (-7)(-7)(-7)] - [(-7)(-7) + (7)(7)]
(-343 + -343) - (49 + 49)
-686 - 98 = -784
The answer is a) -784 :)

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Sunset, inc., has a book value of equity of $14,865. long-term debt is $8,675. net working capital, other than cash, is $2,315.

juin [17]

Balance sheet equation states that:

Assets, A = Liabilities, L + Equity, E => A=L+E

In the current case,
L = Long term debt + Current liabilities = $8,675+$1,865 = $10,540
E = $14,865

Therefore,
A = 14,865 +10,540 = $25,405

Now,
Current assets (excluding cash) = current liabilities+Net working capital, other than cash = $1,865+$2,315 = $4,180

Additionally,
A = Fixed assets+Current assets (excluding cash) + Cash

Therefore,
Cash = 25,405-20,660-4,180 = $565

8 0

3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

<u>Find the distance BC</u>

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

<u>Find the distance DC</u>

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

<u>Find the area of the triangle</u>

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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Alex Ar [27]

Answer: 1/5 x = 10 * 1/5. 1/5x = 2. x = 2*5 = 10

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AveGali [126]

Answer:

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Step-by-step explanation:

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The numbers -5,7,-18,and 0 are examples of

olga_2 [115]

Answer:

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Step-by-step explanation:

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