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2 years ago

5

SURFACE AREA PLEASE HELP

1 answer:

disa [49]2 years ago

6 0

Answer:

486 yd^2

Step-by-step explanation:

Surface area is just finding the area of each face in a figure and adding it all up.

For the surface area of a cube, use this formula:

(a^2) 6

(a is the side length) a^2 is the area of one face of a cube, then multiply it by 6 since there are 6 faces on a cube.

Use formula with given dimensions:

(9^2) 6 = 486

Surface area is measured in square yards

(yards in this case)

Therefore, the surface area of the cube is 486 yd^2

Hope this helps!

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2 years ago

At a car dealership yesterday, the ratio of trucks sold to cars sold was 5.6. If the dealership sold 30 cars, how many trucks we

aleksley [76]

Answer:

25

Step-by-step explanation:

ratio 5:6

$\frac{5}{6} = \frac{x}{30}$

6x = 5(30)

6x = 150

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3 0

2 years ago

Please help asap!!!

Tatiana [17]

Answer:

$w = 6$

Step-by-step explanation:

ST = w + 6,

PR = w

From the diagram given, we can deduce that PR is the midsegment of ∆QST. Therefore, according to the midsegment theorem:

PR = ½ of ST

Plug in the values into the equation and solve for w.

$w = \frac{1}{2}(w + 6)$

$w = \frac{w}{2} + 3$ (distributive property of equality)

$w - 3 = \frac{w}{2}$ (subtraction property of equality)

$2(w - 3) = \frac{w}{2}*2$ (multiplication property of equality)

$2w - 6 = w$

$2w - 6 - 2w= w - 2w$ (subtraction property of equality)

$- 6 = - w$

Divide both sides by -1

$6 = w$

$w = 6$

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3 years ago

According to general equation for conditional probability, if P(A^B) = 2/3 and P(B) = 3/4, what is P(A|B)?

Alexxx [7]

Answer:

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Step-by-step explanation:

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2 years ago

Unit 4 Test, Part 2: Congruence and Constructions<br> Help with my math please

lakkis [162]

Answer/Step-by-sep explanation:

1. Given:

∆NMK ≅ ∆TRP

$\overline{NM} = 20$

$\overline{MK} = 15$

$\overline{KN} = 25$

$\overline{TR} = 3x - 1$

a. To complete the congruent statement, thus: ∆MNK ≅ ∆RTP

b. The side that is congruent to $\overline{TR}$ is $\overline{NM}$ . Thus:

$\overline{TR}$ ≅ $\overline{NM}$

c. Since $\overline{TR}$ ≅ $\overline{NM}$ , therefore:

$\overline{TR} = \overline{NM}$

$3x - 1 = 20$ (substitution)

Add 1 to both sides

$3x = 20 + 1$

$3x = 21$

Divide both sides by 3

$x = \frac{21}{3}$

$x = 7$

2. a. Slope of LK = $\frac{rise}{run} = \frac{4}{3}$

Slope of LM = $\frac{rise}{run} = -\frac{3}{5}$

b. ✍️Length of LK is the distance between L(-7, 4) and (-4, 8):

$Lk = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$Lk = \sqrt{(-4 -(-7))^2 + (8 - 4)^2}$

$Lk = \sqrt{(3)^2 + (4)^2}$

$Lk = \sqrt{9 + 16}$

$Lk = \sqrt{25}$

$Lk = 5$

✍️Length of LM is the distance between L(-7, 4) and (-2, 1):

$LM = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$LM = \sqrt{(-2 -(-7))^2 + (1 - 4)^2}$

$LM = \sqrt{(5)^2 + (-3)^2}$

$LM = \sqrt{25 + 9}$

$LM = \sqrt{34}$

$LM = 5.8$ (nearest tenth)

∆KLM is not an isosceles ∆ because it does not has two equal side lengths. This we can see because LK and LM are not equal.

Therefore, Anthony is incorrect. Am isosceles ∆ has two equal sides.

8 0

3 years ago