<span>a. The magnitude of the vector is doubled as well.
Let's say we have a 2-dimensional vector with components x and y.
It's magnitude lâ‚ is given by:
lâ‚ = âš(x² + y²)
If we double the components x and y, the new magnitude lâ‚‚ is:
lâ‚‚ = âš((2x)² + (2y²))
With a bit of algebra...
lâ‚‚ = âš(4x² + 4y²)
lâ‚‚ = âš4(x² + y²)
lâ‚‚ = 2âš(x² + y²)
We can write the new magnitude lâ‚‚ in terms of the old magnitude lâ‚.
lâ‚‚ = 2lâ‚
Therefore, the new magnitude is double the old one.
It should be clear that this relationship applies to 3D (and 1D) vectors as well.
b. The direction angle is unchanged.
The direction angle θ₠for a 2-dimensional vector is given by:
θ₠= arctan(y / x)
If we double both components, we get:
θ₂ = arctan(2y / 2x)
θ₂ = arctan(y / x)
θ₂ = θâ‚
The new direction angle is the same as the old one.</span>
V=vnaut+at 0(want it to stop)=25+-8t(negative accel cuz its deceling)
-25/-8=t t=3.125 seconds or with sig figs 3.1 seconds
x=xnaut+vnaut*time+1/2*a*time^2
x(where it ends up)=0(we start distance from when it started to brake)+25*3.1+1/2*-8*3.1^2=39.06 meters or 39.1 meters
x=0+25*3.1-.5*8*3.1^2 is the same equation as above with nothing written in. Are you in physics ap or reg? either way friend me lol(just joined website tonight)
For each one . . .
-- some part of your body has to move
-- you convert some chemical energy into kinetic energy when you make muscles move
-- a human being can do it but an animal can't.
Wellll, maybe a monkey can lift a box. 2 out of 3 ain't too bad.
Answer:
a = 2 m/s²
v₄ = 8 m/s
Explanation:
We can find the final speed at the end of eight second by using first equation of motion:
where,
vf = final velocity at 8th second = 16 m/s
vi = initial velocity = 0 m/s
a = acceleration = ?
t = time = 8 s
Therefore, using the values in the equation we get:
<u>a = 2 m/s²</u>
<u></u>
Now, we can apply same equation of motion for 4 seconds of motion to find the velocity at the end of 4th second (v₄):
<u>v₄ = 8 m/s</u>
it will remain the same. only voltage will be changed
