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fiasKO [112]
3 years ago
13

Verify the law of moment.​

Physics
2 answers:
larisa86 [58]3 years ago
4 0

Explanation:

TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTIING ON A BODY S ,KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE,THE SUM OF THE CLOCKWISE MOMENTS ,IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.

<h2>please mark me brainlist :)</h2>
PilotLPTM [1.2K]3 years ago
3 0

Answer:

TO VERIFY THE PRINCIPLE OF MOMENTS WHICH STATES THAT IF A NUMBER OF COPLANAR FORCES ACTING ON A BODY, KEEP IT IN EQUILIBRIUM AND THEIR MOMENT ARE TAKEN ABOUT ANY POINT IN THEIR PLANE, THE SUM OF THE CLOCKWISE MOMENTS,  IS EQUAL TO SUM OF ANTICLOCKWISE MOMENT.

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Why do yall not hate us country people?
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Answer:

Because we don't?

Explanation:

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3 years ago
How much time does it take light from a flash camera to reach a subject 6.0 meters across a room in scientific notation?
wariber [46]

The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.

<u>Explanation:</u>

<u>Given</u>

t=?

d=6m

v=3*10^8 m/s

we  have,  v=d/t

here t=d/v

t=6m/3*10^8 m/s

v=2*10^-8 m/s

The time it takes light from a flash camera to reach a subject 6.0 meters across a room in scientific notation is 2.0 *10^-8 s.

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3 years ago
How large a band of frequencies does each television broadcasting channel get ?
k0ka [10]

Answer:

Since the waves must carry a great deal of visual as well as audio information, each channel requires a larger range of frequencies than simple radio transmission. TV channels utilize frequencies in the range of 54 to 88 MHz and 174 to 222 MHz. (The entire FM radio band lies between channels 88 MHz and 174 MHz.)

8 0
3 years ago
Read 2 more answers
Peter is a middle-aged, overweight man who is trying to decrease his body circumference. How could the serving size on a nutriti
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3 0
3 years ago
A. How long does it take light to travel through a 3.0-mm-thick piece of window glass?
hodyreva [135]

Answer:

a) 1.517\times10^{-11} s

b) 3.41 mm

Explanation:

a)

We take the speed of light, c = 3.0\times10^8 m/s and the refractive index of glass as 1.517.

Speed = distance/time

Time = distance/speed

Refractive index, n = speed of light in vacuum / speed of light in medium

n=\dfrac{c}{s}

s=\dfrac{c}{n}

t=\dfrac{d}{c/n}

t=\dfrac{dn}{c}

t=\dfrac{3\times10^{-3}\times1.517}{3.0\times10^8}

t=1.517\times10^{-11}

b)

We take the refractive index of water as 1.333.

Speed in water = speed in vacuum / refractive index of water

Distance = speed * time

d=s\times t

d=\dfrac{c}{n_w}\times \dfrac{3\times10^{-3}\times1.517}{c}

d=\dfrac{3\times10^{-3}\times 1.517}{1.333}

d = 3.41 mm

6 0
4 years ago
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