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Lemur [1.5K]
3 years ago
14

A 1200kg car moving at 25m/s has the brakes applied with a deceeration of 8.0m/s^2. How far does the car travel before it stops?

Physics
1 answer:
Lostsunrise [7]3 years ago
5 0
V=vnaut+at 0(want it to stop)=25+-8t(negative accel cuz its deceling)
-25/-8=t t=3.125 seconds or with sig figs 3.1 seconds
x=xnaut+vnaut*time+1/2*a*time^2
x(where it ends up)=0(we start distance from when it started to brake)+25*3.1+1/2*-8*3.1^2=39.06 meters or 39.1 meters 
x=0+25*3.1-.5*8*3.1^2 is the same equation as above with nothing written in. Are you in physics ap or reg? either way friend me lol(just joined website tonight)
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I hope it helps, Regards.
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4 years ago
A block of cheese is sliding up an inclined surface that is not smooth.
labwork [276]

Answer:

I cant fit the entire picture but this should help

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3 years ago
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In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube le
expeople1 [14]

Answer:

The  value  is   m \approx   310

Explanation:

From the question we are told that

     The  focal length of the objective is  f_o =  1.0 \ cm

    The  focal length of the eyepiece is  f_e  =  2.0 \  cm

    The  tube length is  L  =  25 \  cm

Generally the magnitude of the overall magnification is mathematically represented as

            m =  m_o  *  m_e

Where  m_o is the objective magnification which is mathematically represented as

        m_o  =  \frac{L}{f_o }

=>      m_o  =  \frac{25}{1 }

=>      m_o  =  25

m_e is the eyepiece magnification which is mathematically evaluated as

     m_e  =  \frac{L }{f_e }

     m_e  =  \frac{25 }{ 2}

      m_e  =  12.5 \  cm

So

    m =  25 * 12.5

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6 0
3 years ago
A speeding truck travels in the positive x direction. It hits a car traveling in the positive y direction. The vehicles are defo
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Answer:

B. Kinetic energy of the system is partially used up in the deformation of the vehicles.

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3 years ago
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2. Two charges at fixed locations produce an electric field as shown
vagabundo [1.1K]

Answer:

sum of the two forces as both point to the right is a force that points to the right,

Explanation:

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indicate that the charge at y is negative, we analyze the direction of the force created by each charge

Charge A

as the electric field is incoming the charge is negative and as the test charge is negative both repel each other, consequently the force points to the right

Charge B

in this case the electric field lines are salient, therefore the charge is positive, consequently the force on the charge at y is attractive and points to the right

the sum of the two forces as both point to the right is a force that points to the right, that is, in the direction of the charge located at B

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