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Illusion [34]
3 years ago
15

What is the greatest common factor of the following monomials: 12g^5h^4 g^5h^2

Mathematics
1 answer:
muminat3 years ago
6 0

Answer:

g^5h^2

Step-by-step explanation:

12g^5h^4, g^5h^2

This is one way of doing it. Break down every number and every variable into a product of the simplest factors. Then see how many of each factor appear in both monomials.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

So far you see every single prime factor of each monomial.

Now I will mark the ones that are present in both. Those are the common factors.

12g^5h^4 = 2 * 2 * 3 * g * g * g * g * g * h * h * h * h

g^5h^2 = g * g * g * g * g * h * h

The greatest common factor is the product of all the factors that appear in both monomials.

GCF = g * g * g * g * g * h * h = g^5h^2

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3 years ago
(6m^3 -16m^2 + 15m - 40) / (2m^2 + 5)
Helen [10]
        6m3 - 16m2 + 15m - 40<span> Simplify ————————————————————— 2m2 + 5 </span>Checking for a perfect cube :

<span> 4.1 </span>  <span> 6m3 - 16m2 + 15m - 40</span>  is not a perfect cube 

Trying to factor by pulling out :

<span> 4.2 </span>     Factoring: <span> 6m3 - 16m2 + 15m - 40</span> 

Thoughtfully split the expression at hand into groups, each group having two terms :

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Pull out from each group separately :

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Group 2: <span>  (3m - 8) • (2m2)</span>
               -------------------
Add up the two groups :
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4 0
3 years ago
252 calories in 4 servings is how many calories per serving?
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Divide the number of calories by the number of servings

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Hello!

Answer:

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Hope this helps!

5 0
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