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maksim [4K]
3 years ago
6

How many atoms are in 8 grams of helium

Chemistry
1 answer:
Mrrafil [7]3 years ago
8 0
12 x 10^23 atoms, i hope this helps
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What information about a molecule can you determine from its<br> chemical formula?
Ira Lisetskai [31]

Answer:

Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the number of atoms of each element present in each molecule is shown as a subscript following that element's symbol.

6 0
3 years ago
Which term refers to compounds with the same molecular formula but different structural formulas?
GREYUIT [131]

Answer:

Isomers

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6 0
3 years ago
A buffer is prepared by adding 300. 0 ml of 2. 0 mnaoh to 500. 0 ml of 2. 0 mch3cooh. what is the ph of this buffer? ka= 1. 8 10
Anton [14]

The Henderson-Hasselbalch equation can be used to determine the pH of the buffer from the pKa value. The pH of the buffer will be 4.75.

<h3>What is the Henderson-Hasselbalch equation?</h3>

Henderson-Hasselbalch equation is used to determine the value of pH of the buffer with the help of the acid disassociation constant.

Given,

Acid disassociation constant (ka) = 1. 8 10⁻⁵

Concentration of NaOH = 2.0 M

Concentration of CH₃COOH = 2.0 M

pKa value is calculated as,

pKa = -log Ka

pKa = - log (1. 8 x 10⁻⁵)

Substituting the value of pKa in the Henderson-Hasselbalch equation as

pH = - log (1. 8 x 10⁻⁵) + log [2.0] ÷ [2.0]

pH = - log (1. 8 x 10⁻⁵) + log [1]

= 4.745 + 0

= 4.75

Therefore, 4.75 is the pH of the buffer.

Learn more about the Henderson-Hasselbalch equation here:

brainly.com/question/27751586

#SPJ4

6 0
1 year ago
A radioactive sample has a half-life of 5 hours. What fraction of the sample will be left after 15 hours?​
DedPeter [7]

Explanation:

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6 0
3 years ago
He standard reduction potentials of lithium metal and chlorine gas are as follows: reaction reduction potential (v) li+(aq)+e−→l
AURORKA [14]

 2 Li(s)  +Cl₂→  2 Li⁺ (aq)  + 2Cl⁻ (aq)

The cell potential   of  the reaction above   is +4.40V

<em><u>calculation</u></em>

Cell  potential  =∈° red - ∈° oxidation

in  reaction above  Li  is  oxidized from oxidation state 0 to +1 therefore the∈° oxid = -3.04

  Cl  is  reduce   from oxidation  state 0 to -1 therefore  the ∈°red = +1.36 V

cell  potential is therefore = +1.36 v -- 3.04  = + 4.40 V

3 0
3 years ago
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