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3 years ago

54 Identify the type of bonding in solid potassium.

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4 0

Base on the question and in my further research and investigation about the said problem that states to identify the type of bonding in solid potassium, I would say that the bondings are metallic bonding and metallic. I hope you are satisfied with my answer and feel free to ask for more

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In the nuclear transmutation, 168O (?, α)137N, what is the bombarding particle? In the nuclear transmutation, O (?, )N, what is

xeze [42]

Answer:

The bombarding particle is a Proton

Explanation:

A Nuclear transmutation reaction occurs when radioactive element decay, usually converting them from one element/isotope into another element. Transmutation is the process which causes decay, generally, alpha or beta.

¹⁶₈O(P,alpha) ¹³₇N, can be written as

¹⁶₈O + x goes to ¹³₇N + ⁴₂He

Where x can be anything, balancing the equation in order to give us the correct amount of proton number and nucleus number

16 + x = 13 + 4

x = 17 – 16 = 1, Hence we can say that x = ¹₁P

Here we can clearly see the bombarding particle is ¹₁P (proton). The ejected particle being ⁴₂He which is also known as an alpha particle

5 0

3 years ago

A student sees a commercial that claims a new dishwasher is energy efficient. Compared to less efficient dishwashers, this means

zaharov [31]

It’s either a or b but I’m not sure

4 0

2 years ago

What is the method of seperating inmisible liquid<br>

nikitadnepr [17]

Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.

6 0

2 years ago

A first-order reaction has a half-life of 16.7 s . How long does it take for the concentration of the reactant in the reaction t

andrew11 [14]

It takes 33.4 s for the concentration of A to fall to one-fourth of its original value.

A <em>half-life</em> is the time it takes for the concentration to fall to half its original value.

Assume the initial concentration is 1.00 mol/L. Then,

$\text{1.00 mol/L }\stackrel{\text{1st half-life }}{\longrightarrow}\text{ 0.50 mol/L } \stackrel{\text{ 2nd half-life }}{\longrightarrow}\text{0.25 mol/L}\\$

The concentration drops to one-fourth of its initial value in two half-lives.

∴ Time = 2 × 16.7 s = 33.4 s

5 0

3 years ago

Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to

viva [34]

The theoretical yield of silver chloride, AgCl is 5.2109 g

The balanced equation for the reaction is given below:

Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AICI₃ = 133.34 g/mol

Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g

Molar mass of AgCl = 143.32 g/mol

Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>

<h3>SUMMARY</h3>

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Therefore,

1.616 g of AICI₃ will react to produce = $\frac{1.616 * 429.96}{133.34}$ = 5.2109 g of AgCl.

Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g

Learn more: brainly.com/question/24653699

3 0

3 years ago