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3 years ago

Can someone give me periodic table till 30?

Chemistry

1 answer:

inysia [295]3 years ago

6 0

1. H (Hydrogen)

2. He (Helium)

3. Li (Lithium)

4. Be (Beryllium)

5. B (Boron)

6. C (Carbon)

7. N (Nitrogen)

8. O (Oxygen)

9. F (Fluorine)

10. Ne (Neon)

11. Na (Sodium)

12. Mg (Magnesium)

13. Al (Aluminium)

14. Si (Silicon)

15. P (Phosphorus)

16. S (Sulfur)

17. Cl (Chlorine)

18. Ar (Argon)

19. K (Potassium)

20. Ca (Calcium)

21. Sc (Scandium)

22. Ti (Titanium)

23. V (Vanadium)

24. Cr (Chromium)

25. Mn (Manganese)

26. Fe (Iron)

27. Co (Cobalt)

28. Ni (Nickel)

29. Cu (Copper)

30. Zn (Zinc)

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In preparation for a demonstration, your professor brings a 1.50−L bottle of sulfur dioxide into the lecture hall before class t

solmaris [256]

Answer:

4.81 moles

Explanation:

The total pressure of the gas = Pressure at which gauge reads zero + pressure read by it.

Pressure at which gauge reads zero = 14.7 psi

Pressure read by the gauge = 988 psi

Total pressure = 14.7 + 988 psi = 1002.7 psi

Also, P (psi) = P (atm) / 14.696

Pressure = 1002.7 / 14.696 = 68.2297 atm

Temperature = 25 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (25 + 273.15) K = 298.15 K

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

68.2297 atm × 1.5 L = n × 0.0821 L.atm/K.mol × 298.15 K

⇒n = 4.81 moles

4 0

3 years ago

How much water should be added to 4.3 moles of LiBr to prepare a 2.05 m solution?

arsen [322]

Answer:

2.1 kg of water

Explanation:

Step 1: Given data

Moles of lithium bromide (solute): 4.3 moles

Molality of the solution (m): 2.05 m (2.05 mol/kg)

Mass of water (solvent): ?

Step 2: Calculate the mass of water required

Molality is equal to the moles of solute divided by the kilograms of solvent.

m = moles of solute/kilograms of solvent

kilograms of solvent = moles of solute/m

kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg

8 0

2 years ago

What must occur in order for a chemical reaction to be specifically classified as endothermic instead of exothermic?

Alla [95]

Answer: B- Chemical bonds are formed. Energy is released in the form of heat.

Explanation: I hoped that helped !

6 0

2 years ago

Read 2 more answers

A piece of high-density Styrofoam measuring 24.0 cm by 36.0 cm by 5.0 cm floats when placed in a tub of water. When a 1.5 kg boo

zheka24 [161]

Explanation:

The given data is as follows.

Width of Styrofoam = 24.0 cm

Length of Styrofoam = 36.0 cm

Height of Styrofoam = 5.0 cm

Therefore, volume of the Styrofoam will be calculated as follows.

Volume = length × width × height

= (36.0 × 24.0 × 5.0) $cm^{3}$

= 4320 $cm^{3}$

or, = $4.32 \times 10^{3} cm^{3}$

As Styrofoam partially sinks at 3.0 cm and total height of Styrofoam is 5.0 cm. Hence, height of Styrofoam above the water is (5.0 - 3 cm) = 2 cm.

So, volume of water displaced is as follows.

24.0 cm × 36.0 cm × 2.0 cm

= $1.73 \times 10^{3} cm^{3}$

Hence, mass of displaced water is as follows.

mass = density × volume

= $1.00 g/cm^{3} \times 1.73 \times 10^{3} cm^{3}$

= $1.73 \times 10^{3} g$

Since, book is placed on the Styrofoam. Therefore, mass of water displaced is also equal to the following.

Mass of water displaced = mass of book + mass of Styrofoam

$1.73 \times 10^{3} g$ = 1500 g + mass of Styrofoam

(1730 - 1500) g = mass of Styrofoam

mass of Styrofoam = 230 g

Therefore, calculate the density of Styrofoam as follows.

Density = $\frac{mass}{volume}$

= $\frac{230}{4.32 \times 10^{3} cm^{3}}$

= $53.24 \times 10^{-3} g cm^{-3}$

Thus, we can conclude that the density of Styrofoam is $53.24 \times 10^{-3} g cm^{-3}$ .

4 0

2 years ago

How many carbon atoms are there in one molecule of CH3FO?

Vlad1618 [11]

Answer:

Brainliest pls

Explanation:

1 mole of a substance contains Avagadro’s number of particles,

i.e. 6.023*10^23

By unitary method,

5 moles of oxygen contains 5 times the Avagadro’s number of particles

i.e. 5* (6.023*10^23) = 3.0115*10^24 number of particles.

Now, the further answer depends on what particles the question concentrates on.

If number of atoms are asked , the above answer must be multiplied by 2, because oxygen is a diatomic gas and each atom contributes to be a particle.

therefore, 5 moles of oxygen has 6.023*10^24 atoms.

If number of molecules asked, the above answer is directly written...

8 0

1 year ago

Can someone give me periodic table till 30?​

Can someone give me periodic table till 30?