There are 5.66 moles of hydrogen in the sample of talc(hydrated magnesium silicate).
Given,
Talc formula is 
moles of magnesium = 8.5 moles
The stoichiometry of magnesium and hydrogen is 3 : 2,
So 3 moles of magnesium is equivalent to 2 moles of hydrogen.
Then 8.5 moles of magnesium is equivalent to
=5.6666 moles
<h3>Talc </h3>
Talc(hydrated magnesium silicate), often known as talcum, is a type of clay mineral made up of hydrated magnesium silicate, having the formula Mg3Si4O10(OH)2. Baby powder is made of powdered talc, frequently mixed with corn starch. This mineral serves as a lubricant and thickening agent. It serves as a component in paint, pottery, and roofing materials. It serves as a key component in many cosmetics. It can be found as foliated to fibrous aggregates and in a remarkably uncommon crystal form. It is foliated with a two-dimensional platy form, has a flawless basal cleavage, and an irregular flat fracture.
Talc(hydrated magnesium silicate), the softest mineral, is assigned a value of 1 on the Mohs scale of mineral hardness, which is based on scratch hardness comparisons.
Learn more about Talc here:
brainly.com/question/24082743
#SPJ4
Answer:
3 moles
Explanation:
So, approximately 3 moles of NaNO3 can be obtained, by reacting 253 grams of Na2CrO4. Also, the number of moles is a dimensionless quantity.
<span> As we know that MgI2 (magnesium iodide) when dissociated it gives more ions than the KI so it has more boiling point as its boiling point is high it means that it boils more so it has low vapor pressure and freezing point
On the other hand as we know that KI dissociates into two ions so so it has high freezing and vapor pressure
hope it helps</span>
Question 1: A material that causes a wave to bounce off it is called the. Answer : Reflection
Question 2: A material that takes in a wave when the wave hits is called the. Answer: Absorber
We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L