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jek_recluse [69]
3 years ago
9

What is helium an example of? element compound atomic number subatomic particle​

Chemistry
2 answers:
fgiga [73]3 years ago
4 0

Answer:

atomic number

Explanation:

hope this helps

Hatshy [7]3 years ago
3 0
I believe its element.
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Q. What phase change occurs at letter A?
svp [43]

Answer:

Where is the picture? Can't answer without it.

7 0
3 years ago
Nitrous oxide (N2O) is used as an anesthetic (laughing gas) and in aerosol cans to produce whipped cream. It is also a potent gr
scZoUnD [109]

Answer:

five half lives

Explanation:

Half-life is the time required for a quantity to reduce to half of its initial value.

How many half lives it would take to reach 3.13% form 100% of it's initial concentration:

100% - 50% : First Half life

50% - 25%: Second Half life

25% - 12.5%: Third Half life

12.5% - 6.25%: Fourth Half life

6.25% - 3.125%: Fifth Half life

This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.

3 0
3 years ago
I rlly need help with my science hwk its due in tomorrow and I am stuck can any one help me plzz :)
Debora [2.8K]

Answer:

Sulfur dioxide relased by the industry=

25%

Explanation:

The amount of sulfur dioxide relased by the industry can be calculated by looking at the values of the other; transport and electricity generation. Since electricity generated sulfur dioxide is 69% + 6% of transport that equals 75%. Pie diagrams always equal a total of 100%.

so simply you minus 75 from 100: 100-75=25%.

7 0
4 years ago
Think about what would happen if this substance were first in the solid phase, then melted in a liquid. What can you say about t
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Answer:

The melting point of the solid is higher in temperature then it is compared to the freezing point of the liquid.

Explanation:

3 0
3 years ago
A silver block, initially at 55.6∘C, is submerged into 100.0 g of water at 24.5∘C in an insulated container. The final temperatu
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Answer:

m_{Ag} = 175.987\,g

Explanation:

The First Law of Thermodynamics helps to determine the mass of the silver block:

m_{Ag}\cdot \left(0.235\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (55.6^{\textdegree}-27.3^{\textdegree}C) = (100\,g)\cdot \left(4.18\,\frac{J}{g\cdot ^{\textdegree}C} \right)\cdot (27.3^{\textdegree}C-24.5^{\textdegree}C)

The mass of the silver block is:

m_{Ag} = 175.987\,g

7 0
3 years ago
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