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Nikolay [14]
4 years ago
12

Please help asap 50 pts

Mathematics
2 answers:
Gala2k [10]4 years ago
7 0
The volume of the rectangular prism:

V = length × width × height

60x^3+145x^2+70x=5x(12x^2+29x+14)=5x(12x^2+21x+8x+14)\\\\=5x[3x(4x+7)+2(4x+7)]=5x(4x+7)(3x+2)

Answer: A.\ 5x(4x+7)(3x+2)
adell [148]4 years ago
4 0
The correct answer would be A.
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You want to build a greenhouse from at most 500 square feet of material in the shape of a half cylinder. The surface area of the
dybincka [34]
<span>Expression for h is h = 500/(pi * r) - r Range of values for r = (0, 10sqrt(5/pi)] First, let's substitute the maximum area of the greenhouse into the provided equation. 500 = pi * r * h + pi * r^2 Now solve for h 500 = pi * r * h + pi * r^2 500 - pi * r^2 = pi * r * h (500 - pi * r^2) / pi * r = h 500/(pi * r) - r = h The minimum value for r is just above 0, since at 0, you're attempting to divide by 0. The maximum value for r is where h = 0, so let's substitute 0 for h and solve for r, giving 500/(pi * r) - r = h 500/(pi * r) - r = 0 500/(pi * r) = r 500 = pi * r^2 500/pi = r^2 sqrt(500/pi) = r 10sqrt(5/pi) = r So maximum r is approximately 12.616 ft. The range of values for r is (0, 10sqrt(5/pi)] e.g. You're not allowed to quite reach the lower limit since that would attempt to divide by 0, but you're allowed to go all the way to the upper limit.</span>
4 0
3 years ago
A flagpole is 15 feet tall and casts a shadow that is 20 feet long. What is the distance from the end of the shadow to the top o
MrRissso [65]
Since the flagpole makes a 90 degree angle to the ground, the height is 15 feet tall and the length of the triangle is 20 feet long. You can use the Pythagorean theorem to find out “c”, but since this is a “3,4,5” triangle, you multiply 5 by 5 to get 25, which is the hypotenuse. Therefore, 25 feet is the answer. •hope this helps!•
8 0
4 years ago
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