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SVEN [57.7K]
3 years ago
7

Explain how to identify a starting position on a line.

Physics
2 answers:
4vir4ik [10]3 years ago
8 0

Sample Response: Pick a reference point on the line to be the zero position. Determine the direction and measure the distance from zero in standard units.

-The reference point is set on the line.

-The distance from that reference point can be used to describe movement.

-Standard units of measurement can be used to identify the distance from the reference point.

Yuliya22 [10]3 years ago
7 0
A fully shaded bubble with a line going right.
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The “turning effect of a force” (T = F * r) is:
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Answer:

b and e

Explanation:

r x F is the formula for torque.

The "turning effect" or torque happens when concentric forces rotate an object along said center.

a) False because T = Fr = Ia (a = angular acceleration)

b) True

c) False. L = Iw (w = angular velocity), which does not equal Ia

d) False. It is torque, not the product of torque and something else

e) True.

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2. During inter phase the cell copies its DNA, and grows to an appropriate size where it is safe for the cell to split.

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4 0
3 years ago
A child is riding a merry-go-round that has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745 ra
skelet666 [1.2K]

Answer:

So the acceleration of the child will be 8.05m/sec^2

Explanation:

We have given angular speed of the child \omega =1.25rad/sec

Radius r = 4.65 m

Angular acceleration \alpha =0.745rad/sec^2

We know that linear velocity is given by v=\omega r=1.25\times 4.65=5.815m/sec

We know that radial acceleration is given by a=\frac{v^2}{r}=\frac{5.815^2}{4.65}=7.2718m/sec^2

Tangential acceleration is given by

a_t=\alpha r=0.745\times 4.65=3.464m/sec^

So total acceleration will be a=\sqrt{7.2718^2+3.464^2}=8.05m/sec^2

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Gravity prevents planets from flying off at a
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