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MrRa [10]
4 years ago
6

A ball is thrown horizontally from the top of a building 109 m high. The ball strikes the ground at a point 75 m horizontally aw

ay from and below the point of release. What is the speed of the ball just before it strikes the ground? (note: speed is magnitude of velocity at that point).
Physics
1 answer:
Alona [7]4 years ago
4 0

Answer:

The speed of the ball just before it strikes the ground is 15.90 m/s.

Explanation:

Given that,

Height = 109 m

Distance = 75 m

We need to calculate the time

Using formula for horizontal projectile

t=\sqrt{\dfrac{2h}{g}}

Where, h = height

Put the value into the formula

t=\sqrt{\dfrac{2\times109}{9.8}}

t=4.716\ sec

We need to calculate the speed of the ball just before it strikes the ground

Using formula of speed

v =\dfrac{d}{t}

Where, v = speed

d = distance

t = time

Put the value into the formula

v=\dfrac{75}{4.716}

v=15.90\ m/s

Hence, The speed of the ball just before it strikes the ground is 15.90 m/s.

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