Answer:
the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
Explanation:
Given that;
weight of vehicle = 4000 lbs
we know that 1 kg = 2.20462
so
m = 4000 / 2.20462 = 1814.37 kg
Initial velocity 
= 60 mph = 26.8224 m/s
Final velocity 
= 30 mph = 13.4112 m/s
now we determine change in kinetic energy
Δk = 
m( ² - ² )
we substitute
Δk = ×1814.37( (26.8224)² - (13.4112)² )
Δk = × 1814.37 × 539.5808
Δk = 489500 Joules
we know that; 1 kilowatt hour = 3.6 × 10⁶ Joule
so
Δk = 489500 / 3.6 × 10⁶
Δk = 0.13597 ≈ 0.136 kWh
Therefore, the theoretical maximum energy in kWh that can be recovered during this interval is 0.136 kWh
The correct answer is letter c. Enthalpy (H). Entrophy means the measure of the degree of disorder. Gibbs energy formulated by Josiah Willard Gibbs and it is the energy associated with a chemical reaction to do work.Fusion is the combining light nuclei into a heavier nucleus.
Answer:
B
Explanation:
The question does not specify any outside forces that could slow down the ball horizontally. There fore the ball does not accelerate or decelerate horizontally. Therefore, a = 0m/s2
Answer:
網站有中、英文版本，也有繁、簡體版，可通過每頁左上角的連結隨時網站有中、英文版本，也有繁、簡體版，可通過每頁左上角的連結隨時
Explanation:
<span>you must first select an axis of rotation about which to calculate moment arms and torques. </span>
