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V125BC [204]
3 years ago
13

Any ideas for the science fair? I am a 7th grader but looking for a first-place type of project.Thanks!

Physics
1 answer:
mihalych1998 [28]3 years ago
7 0
U can do what is the strongest paper towel
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A person of mass m is standing on the surface of the Earth, of mass M E . What is the acceleration that the Earth experiences du
Lana71 [14]

Answer:

a_E=\dfrac{Gm}{r^2}

Explanation:

M_E = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6371000 m

m = Mass of person

The force on the person will balance the gravitational force

M_Ea_E=\dfrac{GmM_E}{r^2}\\\Rightarrow a_E=\dfrac{Gm}{r^2}

The acceleration that the Earth will feel is a_E=\dfrac{Gm}{r^2}

7 0
3 years ago
Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. His
Ludmilka [50]

Answer:

12 m/s west

Explanation:

4 0
3 years ago
Read 2 more answers
A ship sails east from a harbor for 16 nautical miles. it then sails in the direction of n 55 e for 18 nautical miles. how far i
Katena32 [7]
<span> Use the Law of Cosines, where you have a triangle with included angle of 145 degrees and sides of 16 and 18. You are then solving the equation: </span>

<span>d^2 = 16^2 + 18^2 - 2(16)(18)cos(145)        </span>
8 0
3 years ago
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Choose the correct statement regarding the sign conventions for lenses.
Savatey [412]

Answer:

a) false

b) True

c) True

d) False

e) False

Explanation:

a) False

For a diverging lens, the focal length is negative while it is positive for a converging lens

b) True

Image distances  for virtual images are always negative and it also forms on the the same side of the lens as the object and is enlarged

c) True

d) False

For a diverging lens, the focal length is negative while it is positive for a converging lens

e) False

Image distances  for virtual images are always negative and it also forms on the the same side of the lens as the object and is enlarged

3 0
3 years ago
What is the kinetic energy of a 1200 kg object that is moving at a speed of 24 m/s?
maria [59]
Kinetic Energy = 1/2mv^2
m= 1200kg
v= 24 m/s

KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N
4 0
3 years ago
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