Gravity prevents planets from flying off at a

Help me help me help me

spin [16.1K]

I think d because they are both increasing

7 0

2 years ago

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A light has a wavelength of 5.06x10-7m. what is the frequency of the light?

Artyom0805 [142]

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

<h3>Introduction</h3>

Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or $\sf{3 \times 10^8}$ m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

$\boxed{\sf{\bold{c = \lambda \times f}}}$

With the following condition :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength (m)
f = electromagnetic wave frequency (Hz)

<h3>Problem Solving</h3>

We know that :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength = $\sf{5.06 \times 10^{-7}}$ m.

What was asked :

f = electromagnetic wave frequency = ... Hz

Step by step :

$\sf{c = \lambda \times f}$

$\sf{3 \times 10^8 = 5.06 \times 10^{-7} \times f}$

$\sf{f = \frac{3 \times 10^8}{5.06 \times 10^{-7}}}$

$\sf{f \approx 0.593 \times 10^{8 - (-7)}}$

$\sf{f \approx 0.593 \times 10^{15}}$

$\boxed{\sf{f \approx 5.93 \times 10^{14} \: Hz}}$

<h3>Conclusion :</h3>

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

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7 0

1 year ago

One man pushes on the front of a cart while

geniusboy [140]

Answer:

pushes it forward, pushes it backwards and then it moves

7 0

2 years ago

Please help! It has to deal with Newton's 3rd law! 30 points! and if right brainliest!

Lynna [10]

Answer:

Newton's Third Law

His third law states that for every action (force) in nature there is an equal and opposite reaction

Explanation:

5 0

11 months ago

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Light with a wavelength of 495 nm is falling on a surface and electrons with a maximum kinetic energy of 0.5 eV are ejected. Wha

devlian [24]

Answer:

To increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

Explanation:

First, we have to calculate the work function of the element. The maximum kinetic energy as a function of the wavelength is given by:

$K_{max}=\frac{hc}{\lambda}-W$

Here h is the Planck's constant, c is the speed of light, $\lambda$ is the wavelength of the light and W the work function of the element:

$W=\frac{hc}{\lambda}-K_{max}\\W=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{495*10^{-9}m}-0.5eV\\W=2.01eV$

Now, we calculate the wavelength for the new maximum kinetic energy:

$W+K_{max}=\frac{hc}{\lambda}\\\lambda=\frac{hc}{W+K_{max}}\\\lambda=\frac{(4.14*10^{-15}eV\cdot s)(3*10^8\frac{m}{s})}{2.01eV+1.5eV}\\\lambda=3.54*10^{-7}m=354*10^{-9}m=354nm$

This wavelength corresponds to ultraviolet radiation. So, to increase the maximum kinetic energy of electrons to 1.5 eV, it is necessary that ultraviolet radiation of 354 nm falls on the surface.

8 0

3 years ago