Pulsar or also sometimes as a actively rotating accretion disc
We have that the time in seconds, minutes, and hours is



From the Question we are told that
Velocity 
Distance 
Generally the equation for the Time is mathematically given as
Therefore


And


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Where is the rest of the sentence?
The new volume will be ≈26mL
rounded to two significant figures.
Explanation:
This question involves the combined gas law. The equation to use is:
When working with gas laws, the temperature is always in Kelvins. To get Kelvins from a Celsius temperature, add 273.15 to the Celsius temperature.
Answer:
50% of it .
Explanation:
50% of it is illuminated by the Sun.