If you wanted to do calculations with speed (distance/time), which base units would you use

AveGali [126]

Answer:

It is classified as a metal because of its high ductility, malleability, thermal and electrical conductivity and resistance to corrosion. Copper is a mineral used for our everyday use. It is limited and we have to use it wisely because it is not evenly distributed everywhere and also everyone needs it. Copper is element number 29 on the Periodic Table of Elements. It is also used it electronics and wiring.

hope this helped

:)

8 0

3 years ago

The diagram shows a charge moving into an electric field. The charge will most likely leave the electric field near which letter

Simora [160]

you haven't attached the diagram, but i assume that this diagram is what you were talking about

Answer:

near Y

Explanation:

the electric field lines goes from a positive charge to a negative charge. This means that a positive charge would move in the same direction of the field lines, while a negative charge would move in the opposite direction of the field lines. the field lines are created from +vely charged plate to -vely charged plate so the negative charged particles moves towards the lower plate which is positively charged, and opposite to the direction of field lines.

5 0

3 years ago

Find the minimum kinetic energy in MeV necessary for an α particle to touch a 39 19 K nucleus that is initially at rest, assumin

SIZIF [17.4K]

Answer:

KE = 9.6MeV

Explanation:

Given the relationships we understand that,

$q_1 = 19e, q_2 = 2e$

The Potential at point p, is given by the following formula

$V_ {p} = \frac {Kq_1} {r}$

According to the graphic designed, you have,

$V_ {p} = \frac {Kq_1} {(r_1 + r_2)}$

$V_ {p} = \frac {(9 * 10 ^ 9) (19 * 1.6 * 10 ^ {- 15})} {(3.7 + 2) * 10 ^{- 15}}}$

$V_ {p} = 4.8 * 10 ^ 6V$

The kinetic energy of the particle would be given by

$KE = q_2 * V_ {p} = 2e * 4.8 * 10 ^ 6V$

$KE = 9.6MeV$

4 0

3 years ago

There are two containers of equal volumes, each filled with a different gas. Both containers have the same number of moles of ga

Gekata [30.6K]

Answer:

Molecules in container 2 has a higher pressure.

Molecules in container 2 has a greater rms speed.

Molecules in container 2 has a greater kinetic energy.

Molecules in container 2 has a greater thermal energy.

Explanation:

At constant volume and temperature, The number of moles of a gas is proportional to its pressure.

The lower the pressure, the lesser the rms speed of molecules, kinetic energy of the molecules and thermal energy of the molecules, hence the answer above.

7 0

3 years ago

A bowler throws a bowling ball of radius R = 11 cm along a lane. The ball slides on the lane with initial speed vcom,0 = 6.0 m/s

ankoles [38]

Answer:

Explanation:

Radius of the ball is $R=11cm=0.11m$

Initial speed of the ball is $v_{com0}=6.0m/s$

Initial angular speed of the ball is $\omega = 0$

Coefficient of kinetic friction between the ball and the lane

is $\mu =0.35$

Due to the presence of frictional force, ball moves with

decreasing velocity.

(a)

velocity $v_{com0}$ in terms of $\omega$ is

$V_{com0} = -R\omega\\\\=-(0.11m)\omega\\\\= (-0.11\omega)m/s$

(b)

Ball's linear acceleration is given by

$a=-\mu g\\\\=-(0.35) (9.8 m/s^2)\\\\= -3.43m/s^2$

(c)

During sliding, ball's angular acceleration is calculated as

$\alpha=-\frac{\tau}{I}\\\\-\frac{\mu mgR}{(\frac{2}{5}mR^2)}\\\\-\frac{2}{5}\frac{\mu g}{R}\\\\-\frac{2}{5}\frac{(0.35)(9.8)}{0.11}\\\\-77.95rad/s^2$

(d)

The time for which the ball slides is calculated from the

equation of motion is

$V_{cm}= V_{cm0} + at\\\\V_{cm} = V_{cm0} + (-\mu g )t\\\\-0.11\omega=6.0m/s -(3.43m/s^2 )t\\\\-(0.11) (\alpha t) =6.0 m/s - (3.43 m/s^2)\\\\- (0.11)(-77.95 rad/s^2)t = 6.0m/s - (3.43 m/s^2 )t\\\\8.5745t + 3.43t= 6.0\\\\12.0045t = 6.0\\\\t= 0.4998s$

(e)

Distance traveled by the ball is

$X= V_{com,0}+ \frac{1}{2}at^2\\\\= (6.0m/s)(0.4998 s)+ 0.5(-3.43m/s^2) (0.4998 s)^2\\\\=2.57m$

(for)

The speed of the ball when smooth rolling begins is

$V_{cm} = V_{com, 0}+ at\\\\=6.0 m/s +(-3.43m/s^2 )(0.4998 s)\\\\= 4.29m/s$

5 0

3 years ago

Read 2 more answers