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olga2289 [7]
3 years ago
7

40 Newtons

Physics
1 answer:
Kobotan [32]3 years ago
6 0
Although the weight of the spears a different the gravitational forces are the same
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78 million in standard form
Leviafan [203]

Answer:

78 million in standard form is 78,000,000

6 0
3 years ago
Every object in the universe exerts a force on every other object. This force is called
MrMuchimi

Gravity is the correct answer.

6 0
3 years ago
Martin needs to push a box up a ramp.
creativ13 [48]
Uh I think it is inertia but I could be wrong
8 0
3 years ago
An electron moves a 2.0x10^6 meter per the second perpendicular to a magnetic field having a flux density of 2 teslas. What is t
Darina [25.2K]

Answer:

F_B = 6.4*10^-13 N

Explanation:

The magnetic force on the electron, generated by the motion of the electron and the magnetic field is given by:

F_B=qv\ X\ B

q: electron charge = 1.6*10^{-19}C

v: speed of the electron = 2.0*10^6 m/s

B: magnitude of the magnetic field = 2T

However, the direction of B and v are perpendicular between them. So, the angle between vectors is 90°. The magnitude of the magnetic force is:

|F_B|=qvBsin90\°=qvB

You replace the values of q, v and B in the last equation:

|F_B|=(1.6*10^{-19}C)(2.0*10^6m/s)(2T)\\\\|F_B|=6.4*10^{-13}\ N

hence, the magnetic force on the electron is 6.4*10^-23 N

6 0
3 years ago
A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec
Phoenix [80]

Answer:

The particle path will follow

(d) a circular path

Explanation:

When a charged particle having charge of magnitude 'q' enters into a magnetic field such that its velocity vector '\vec{V}' is perpendicular to the direction of the magnetic field '\vec{B}', then it will experience a force, called Lorentz force (\vec{F_{L}}), given by

\vec{F_{L}} = \vec{V} \times \vec{B}

As shown in the figure, the magnetic field is directed perpendicular to the plane and towards the plane (as shown by the circle and 'X'-sign) and the velocity vector is from left to right on the plane.

According to the property of cross-product, the Lorentz force (F_{L}) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path,as shown in the figure.

7 0
4 years ago
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