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3 years ago

______________friction is the type of kinetic friction that is difficult to overcome.

Physics

2 answers:

Burka [1]3 years ago

8 0

Answer:

Explanation:

energy friction

jeyben [28]3 years ago

5 0

Answer:

Kenetic

Explanation:

Idk if i spelled that right

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Sarah is sitting at the top of the slide in the school's playground. Which of the following changes will increase Sarah's kineti

Ray Of Light [21]

B; kinetic energy is anything in motion

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4 years ago

Identifying the guilty party was mainly based on eyewitness accounts during what time period?

kondaur [170]

The time period for guilty party was between 1900-1988.

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3 years ago

Read 2 more answers

What were formed after the big bang theory?

tatuchka [14]

Answer:

neutrons protons electrons

Explanation:

after the Big Bang, the universe was filled with neutrons, protons, electrons, anti-electrons, photons and neutrinos.

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3 years ago

On a distant planet, golf is just as popular as it is on earth. A golfer tees off and drives the ball 3.70 times as far as he wo

Margarita [4]

Answer:

a)H=84.87 m

b)R=565.27 m

Explanation:

Given that

Speed of ball on earth

U=41.2 m/s

θ=31°

We know that

Maximum height in projectile motion given as

$h=\dfrac{U^2sin^2\theta }{2g}$

$h=\dfrac{41.2^2sin^231}{2\times 9.81}$

h=22.94 m

Range in projectile motion given as

$r=\dfrac{U^2sin2\theta }{g}$

$r=\dfrac{41.2^2sin62 }{g}$

r=152.77 m

Given that on distance planet ball moves 3.7 times far more as on earth.

So on the distance planet

The maximum height ,H=3.7 h

H= 3.7 x 22.94

H=84.87 m

The range on distance planet

R=3.7 r

R=3.7 x 152.77 m

R=565.27 m

7 0

3 years ago

At some instant and location the electric field associated with an electromagnetic wave in vacuum has the strength 96.5 V/m. Fin

prisoha [69]

Answer:

B = 32.17 x 10^-8 Tesla

u = 8.24 x 10^-8 J/m^3

P/A = 24.72 W/m^2

Explanation:

E = 96.5 V/m

velocity of light, c = 3 x 10^8 m/s

Let B be the magnetic field.

The relation between the electric field strength and the magnetic field strength is given by

B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla

Let u be the energy density.

$u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}$

$u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}$

u = 8.24 x 10^-8 J/m^3

Let Power flow per unit area is

P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2

7 0

3 years ago