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diamong [38]
3 years ago
10

Solve the quadratic equation by the square root property. (2x + 5)2 = 49

Mathematics
2 answers:
Sergio [31]3 years ago
8 0

This is all if you don't solve as a quadratic equation.

Look at the other answer.

Answer:

<em><u>x = 9.75</u></em>

Step-by-step explanation:

Step 1. Distribute the 2(Do 2 times 2x and 2 tiems 5)

4x + 10 = 49

Step 2. Subtract 10 from both sides.

4x = 39

Step 3. Divide it all by 4 to isolate the variable.

x = 9.75

Anon25 [30]3 years ago
3 0

Answer:

x=1  and x=-6

Step-by-step explanation:

(2x + 5)^2 = 49

Take the square root of each side

sqrt((2x + 5)^2) = ±sqrt(49)

2x+5 = ±7

Subtract 5 from each side

2x+5-5 = 7-5        2x+5-5 = -7-5

2x = 2                   2x  =-12

Divide by 2

2x/2 =2/2                 2x/2  = -12/2

x =1                            x = -6

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A high street store advertises 35% reduction on all clothing items. A dress costs £85 before the reduction. How much does it cos
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£55.25

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What is the value of the fourth term in the geometric sequence
ivanzaharov [21]

Answer:

a(4) = 15/4

Step-by-step explanation:

Here we're told that the first term is a(1) = 30 and that the common factor r = 1/2.

Thus, the geometric sequence formula specific to this case is

a(n) = 30(1/:2)^(n-1).

What is the fourth term?  Let n = 4,

a(4) = 30(1/2)^(4-1), or a(4) = 30(1/2)^(3), or  a(4) = 30(1/8) = 30/8, or, in reduced form,

a(4) = 15/4.

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Which number is the most reasonable estimated difference between 10.85 and 2 1/5?
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Step-by-step explanation:

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MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
2 years ago
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