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zmey [24]
2 years ago
7

A stone is thrown horizontally from the top of a tower at the same instant a ball is droppedvertically. Which object is travelin

g faster when it hits the level ground below?
Physics
1 answer:
Igoryamba2 years ago
5 0

The ball is travelling faster when the two objects hits the level ground below.

<h3>Time of motion of the objects</h3>

The time of motion of the objects depends on height and initial velocity of projection of the objects.

The stone has no initial vertical velocity while the ball has initial vertical velocity.

Thus, the ball is travelling faster when the two objects hits the level ground below.

Learn more about time of motion here: brainly.com/question/2364404

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You might be interested in
you apply 100.0 N of force to a machine. The machine applies 20.0 N of the force to the load. what is the mechanical advantage o
morpeh [17]
Mechanical advantage is 5
100/20
5 0
4 years ago
Read 2 more answers
Someone help me please
sp2606 [1]

Im not fully sure about this. But i believe its A.

For Example: The constant pull of gravity on the moon is way different then on the earth, same with the acceleration of gravity. This is why objects float more on the moon.

-Seth

8 0
3 years ago
Read 2 more answers
Three strings, attached to the sides of a rectangular frame, are tied together by a knot as shown in the figure. The magnitude o
nevsk [136]

The tension in the string marked A is determined as 331.35 N.

<h3>Angle made by A with respect to vertical</h3>

tanθ = Δy/Δx

tanθ = (6 - 1)/(7 - 1) = 0.8333

θ = arc tan(0.8333) = 39.81⁰

with respect to horizontal = 90 - 39.81 = 50.19⁰

<h3>Angle made by B with respect to horizontal</h3>

tanθ = Δy/Δx

tanθ = (9 - 6)/(7 - 5) = 1.5

θ = arc tan(1.5) = 56.31 ⁰

<h3>Angle made by C with respect to horizontal</h3>

tanθ = Δy/Δx

tanθ = (6 - 4)/(14 - 7) = 0.2857

θ = arc tan(0.2857) = 15.95 ⁰

Bcosθ + Aosθ = Ccosθ

Bcos(56.31) + A[cos(50.19)] = 56.3cos(15.95)

0.55B + 0.64A = 54.13 ----- (1)

Bsinθ + Asinθ = Csinθ

Bsin(56.31) + A[sin(50.19)] = 56.3sin(15.95)

0.832B + 0.77A = 15.47---- (2)

Solve (1) and (2)

0.2A = 66.27

A = 66.27/0.2

A = 331.35 N

Thus, the tension in the string marked A is determined as 331.35 N.

Learn more about tension here: brainly.com/question/918617

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5 0
2 years ago
If a person walks 1 km north, 5 km west, 3 km south and 7 km east, find the resultant displacement vecto
alexandr402 [8]

If a person walks 1km north, 5 km West, 3km south, and 7km east, then the resultant displacement vector would be 2.82 km toward the south east direction

What is displacement?

When an object moves in connection to a reference frame, such as when a passenger travels to the back of an airliner or a professor walks to the right in relation to a whiteboard, its position changes. This movement in position is described as displacement.

as stated in the issue If a person goes one kilometre north, five kilometres west, three kilometres south, and seven kilometres east,

The resulting displacement vector, as we know, is the shortest feasible distance between the beginning and ending points

In the horizontal direction, the outcome is

7-5 pointing east

2 kilometres to the eas

In the vertical direction, the outcome is

3–1 km to the south

2 kilometres to the south

$\begin{aligned} \text { Resultant displacement } &=\sqrt{ }\left(2^{2}+2^{2}\right) \\ &=2 \cdot \sqrt{2} \\ &=2.82 \end{aligned}$

As a result, the resulting displacement vector is 2.82 kilometres to the southeast.

Learn more about displacement here

brainly.com/question/10919017

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4 0
1 year ago
The amount of heat needed
Simora [160]
Q = mcθ
 
Where Q = Amount of heat in J
             m = Mass of substance in kg
              θ  = Temperature rise in °C or K
              C = Specific heat capacity in J/kgK

From given data:
Q = 33 kJ = 33 000 J, m= 2.0 kg,   θ  = 80 K,   c = ?

33000 =  2 * c * 80
33000 = 160c
160c   = 33000
       c   =  33000/160 = 206.25

Therefore specific heat capacity is 206.25 J/kgK
4 0
4 years ago
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