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Gre4nikov [31]
3 years ago
5

Consider N non-interacting diatomic molecules stuck on a metal surface. Each molecule can either lie flat on the surface, in whi

ch case it must be aligned to one of two directions, x and y, or it can stand up along the z direction. There is an energy cost e > 0 associated with a molecule standing up, and zero energy for molecules lying flat along x or y directions.
What are the possible energy levels for this system of N particles, and what is the number of microstates associated to each energy level?
Find the entropy and energy of the system as a function of the temperature, T.
What is the probability of a specific molecule standing up?
What is the largest possible value of the energy of the system at any temperature?

Physics
1 answer:
Art [367]3 years ago
7 0

Answer:

Detailed solution given in diagram

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The accepted standard measurement for mass is the A) liter. B) pound. C) Newton. D) kilogram.
andreev551 [17]
D) Kilograms is the standard unit of mass
6 0
3 years ago
Diamond has an index of refraction of 2.419. What is the critical angle for internal reflection inside a diamond that is in air?
SSSSS [86.1K]

Answer:

C) 24.4°

Explanation:

let nd = 2.419 be the index of refraction of diamond and na  = 1.0 be the index of refraction of air  and ∅c be the critical angle.

according to Snell's Law:

sin(∅c) = na/nd

sin(∅c) = (1.0)/(2.419)

      ∅c = 24.4°

4 0
3 years ago
A system absorbed 44 joules of heat from its surroundings. After doing work, the increase in the internal energy of the system i
Lunna [17]
Idk sorry maybe try @amyletbe
6 0
3 years ago
Read 2 more answers
A 3.1 kg ball is dropped from the top of a 38 m tall building. What is the speed of the ball when it is halfway from the buildin
Archy [21]

Answer:

19.3m/s

Explanation:

Use third equation of motion

v^2-u^2=2gh

where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity

insert values to get answer

v^2-0^2=2(9.81m/s^2)(38/2)\\v^2=9.81m/s^2 *38\\v^2=372.78\\v=\sqrt[]{372.78} \\v=19.3m/s

4 0
3 years ago
The heat capacity of object B is twice that of object A. Initially A is at 300 K and B at 450 K. They are placed in thermal cont
ivann1987 [24]

Answer:

The final temperature of both objects is 400 K

Explanation:

The quantity of heat transferred per unit mass is given by;

Q = cΔT

where;

c is the specific heat capacity

ΔT is the change in temperature

The heat transferred by the  object A per unit mass is given by;

Q(A) = caΔT

where;

ca is the specific heat capacity of object A

The heat transferred by the  object B per unit mass is given by;

Q(B) = cbΔT

where;

cb is the specific heat capacity of object B

The heat lost by object B is equal to heat gained by object A

Q(A) = -Q(B)

But heat capacity of object B is twice that of object A

The final temperature of the two objects is given by

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b}

But heat capacity of object B is twice that of object A

T_2 = \frac{C_aT_a + C_bT_b}{C_a + C_b} \\\\T_2 = \frac{C_aT_a + 2C_aT_b}{C_a + 2C_a}\\\\T_2 = \frac{c_a(T_a + 2T_b)}{3C_a} \\\\T_2 = \frac{T_a + 2T_b}{3}\\\\T_2 = \frac{300 + (2*450)}{3}\\\\T_2 = 400 \ K

Therefore, the final temperature of both objects is 400 K.

4 0
3 years ago
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