Answer:Given mass = 4.1kg
Radius = 0.0117m
Velocity V = 8.4m/s
Coefficient of friction = 0.25
Explanation: Below is an attached solution to the problem stated above.
1. The angular acceleration is equal to 524rad/s^2
2. The linear acceleration is equal to 2.45m/s^2
3.the time it takes the ball to begin rolling = 0.98s
4. The distance the ball slides before it begins to roll = 7.05m
Answer:
Centripetal force is equal to 31.55 N
Explanation:
We have given mass of the body m = 8 kg
Radius of the circular path r = 10 m
It is given that it makes 1 revolution in 10 seconds
Distance traveled in 10 seconds is equal to 
Velocity is equal to 
We have to find the centripetal force
Centripetal force is equal to 
So centripetal force will be equal to 31.55 N
Answer:
V = 3.6 volts
Explanation:
From Ohm's Law, we know that:
V = IR
but,
R = ρL/A
Therefore,
V = IρL/A
where,
V = Potential Difference = ?
I = Current = 4 A
ρ = resistivity of copper = 1.68 x 10⁻⁸ Ω.m
L = Length = 70 m
A = Cross-sectional Area = πd²/4 = π(1.29 x 10⁻³ m)²/4 [16 gauge wire has a diameter of 1.29 mm]
A = 1.31 x 10⁻⁶ m²
V = (4 A)(1.68 x 10⁻⁸ Ω.m)(70 m)/(1.31 x 10⁻⁶ m²)
<u>V = 3.6 volts</u>
Answer:
The velocity of charge is 1.1×10⁴
Option(D)
Explanation:
F = q(v×B)
3.5×10-²= (8.4×10-⁴)*(v)*(6.7×10-³)*sin35
v = (3.5)/(8.4×6.7×0.57) × 10⁵
v = 3.5/32.08 × 10⁵
v = 0.109 × 10⁵
v ≈ 1.1 × 10⁴ m/s
