Answer:
The answer is C.
Step-by-step explanation:
Given formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height.
In this case, the initial postion is a platform 30ft above ground so h0=+30
The initial velocity is 38 ft/s straight up into the air so v0=+38
h(t)=-16t2+38t+30
When the object hits the ground, h=0.
h=-16t2+38t+30=0
Simplifying 8t2-19t-15=0
(8t+5)(t-3)=0
t=-5/8 or 3
As time cannot be -ve, t=3s. The answer is C.
Answer:
Yes, I am 99% sure your right.
Answer:
-5 ≤ n ≤ 3
Step-by-step explanation:
Firstly we solve the equation two at a time;
5n + 17 ≥ n - 3
5n - n ≥ -3 - 17
4n ≥ -20
n ≥ -5
-5 ≤ n
n - 3 ≥ -15 + 5n
n - 5n ≥ -15 + 3
-4n ≥ -12
-n ≥ -3
n ≤ 3
Therefore,
5n+17 ≥ n–3 ≥ –15+5n, becomes
-5 ≤ n ≤ 3
Answer:
y = 3x - 5
Step-by-step explanation:
We know that the equation 'y = 3x + ?' intersects the point (1, -2). This means that when x = 1, y = -2 in out equation above. To solve this just plug in the x and y values to get '?'.
Now that we know '?' is -5, we write it back into slope intercept form, so our final answer is y = 3x - 5
40 students prefer vanilla. To get this answer you need to multiply 200 times 0.2 because you are trying to find 20%
