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3 years ago

Find the complete factorization of the expression. 48x + 56xy

Mathematics

1 answer:

meriva3 years ago

7 0

8x(6 + 7y) this is your answer hope it works!

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Bee Paul, store manager for Jay's Appliance, is having a difficult time placing a selling price on a plasma television that orig

Trava [24]

Answer:

400$

Step-by-step explanation:

7 0

3 years ago

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th

Naddika [18.5K]

Answer:

The rocket will hit the ground after about 8.20 seconds.

Step-by-step explanation:

The height of the rocket y, in feet, x seconds after launch is modeled by the equation:

$y=-16x^2+121x+83$

We want to find the time at which the rocket will hit the ground.

If it hits the ground, the height of the rocket y will be 0. Thus:

$0=-16x^2+121x+83$

We can solve for x. Factoring (if possible at all) or completing the square can be tedious, so we can use the quadratic formula:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = -16, b = 121, and c = 83. Substitute:

$\displaystyle x=\frac{-(121)\pm\sqrt{(121)^2-4(-16)(83)}}{2(-16)}$

Simplify:

$\displaystyle x=\frac{-121\pm\sqrt{19953}}{-32}$

Divide everything by -1 and simplify the square root. The plus/minus will remain unchanged:

$\displaystyle x=\frac{121\pm3\sqrt{2217}}{32}$

Therefore, our two solutions are:

$\displaystyle x=\frac{121+3\sqrt{2217}}{32}\approx 8.20\text{ or } x=\frac{121-3\sqrt{2217}}{32}\approx -0.63$

Since time cannot be negative, we can ignore the second solution.

Therefore, the rocket will hit the ground after about 8.20 seconds.

7 0

3 years ago

It is given the quadratic equation (q + 1 )x² - 8x + p = 0,where p and q are constants,has two equal real roots.Express p in ter

Ksju [112]

Step-by-step explanation:

answer is in the photo above

7 0

3 years ago

Read 2 more answers

Rectangle LOSP is shown below. The lengths, in units, of some of the line segments are also shown. Line segments MQ and NR are p

Galina-37 [17]

Answer: c. OSRN

Step-by-step explanation:

Sides of similar shapes are proportional.

For Rectangle LOSP,

Length = LO = 4+6+8 = 18 units

Width = OS= 12 units

Here, $\dfrac{18}{12}=\dfrac{3}{2}$ [proportionality constant]

a. For Rectangle LMQP,

Length = MQ = 12 units

Width = LM = 4 units

Here, $\dfrac{12}{4}=3\neq\dfrac32$

LMQP is not similar to LOSP.

b. Similarly, for LNRP,

Width = LN= 4+6 = 10

length = NR = 12

$\dfrac{12}{10}\neq\dfrac32$

LNRP is not similar to LOSP.

c. For OSRN,

Length = OS = 12

Width = ON = 8

$\dfrac{12}{8}=\dfrac32$

OSRN is similar to LOSP.

d. For MNRQ,

Length= NR = 12

Width = MN = 6

$\dfrac{12}{6}=2\neq\dfrac32$

MNRQ is not similar to LOSP.

Hence, the shape similar to rectangle LOSP is OSRN.

4 0

3 years ago

Can someone help me out my grads are bad

Pani-rosa [81]

Answer:

162

Step-by-step explanation:

9 x 6 = 54

18 x 6 = 108

108 + 54 = 162

8 0

3 years ago