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3 years ago

How does the heat from sun reach earth

Physics

1 answer:

kakasveta [241]3 years ago

3 0

Answer:

The sun heats the earth through radiation. Since there is no medium (like the gas in our atmosphere) in space, radiation is the primary way that heat travels in space. When the heat reaches the earth it warms the molecules of the atmosphere, and they warm other molecules and so on.

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Consult interactive solution 2.22 before beginning this problem. a car is traveling along a straight road at a velocity of +30.0

Inessa05 [86]

Let $a_1$ be the average acceleration over the first 2.46 seconds, and $a_2$ the average acceleration over the next 6.79 seconds.

At the start, the car has velocity 30.0 m/s, and at the end of the total 9.25 second interval it has velocity 15.2 m/s. Let $v$ be the velocity of the car after the first 2.46 seconds.

By definition of average acceleration, we have

$a_1=\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}$

$a_2=\dfrac{15.2\,\frac{\mathrm m}{\mathrm s}-v}{6.79\,\mathrm s}$

and we're also told that

$\dfrac{a_1}{a_2}=1.66$

(or possibly the other way around; I'll consider that case later). We can solve for $a_1$ in the ratio equation and substitute it into the first average acceleration equation, and in turn we end up with an equation independent of the accelerations:

$1.66a_2=\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}$

$\implies1.66\left(\dfrac{15.2\,\frac{\mathrm m}{\mathrm s}-v}{6.79\,\mathrm s}\right)=\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}$

Now we can solve for $v$ . We find that

$v=20.8\,\dfrac{\mathrm m}{\mathrm s}$

In the case that the ratio of accelerations is actually

$\dfrac{a_2}{a_1}=1.66$

we would instead have

$\dfrac{15.2\,\frac{\mathrm m}{\mathrm s}-v}{6.79\,\mathrm s}=1.66\left(\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}\right)$

in which case we would get a velocity of

$v=24.4\,\dfrac{\mathrm m}{\mathrm s}$

6 0

3 years ago

Ramon and sally are observing a toy car speed up as it goes around a circular track. ramon says, "the car's speeding up, so ther

Anestetic [448]

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3 years ago

What type of muscular assessment is the bench press

solmaris [256]

upper body muscular strength

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2 years ago

Ice floats in water because it is______ than matter

Neko [114]

Answer:

Less dense than water

Explanation:

6 0

3 years ago

(hrw8c10p78) Two uniform solid spheres have the same mass, 1.65 kg, but one has a radius of 0.206 m while the other has a radius

Burka [1]

Complete question is:

Two uniform solid spheres have the same mass of 1.65 kg, but one has a radius of 0.206 m and the other has a radius of 0.804 m. Each can rotate about an axis through its center. (a) What is the magnitude τ of the torque required to bring the smaller sphere from rest to an angular speed of 367 rad/s in 14.5 s? (b) What is the magnitude F of the force that must be applied tangentially at the sphere’s equator to give that torque? What are the corresponding values of (c) τ and (d) F for the larger sphere?

Answer:

A) τ = 0.709 N.m

B) F = 3.44 N

C) τ = 10.8 N.m

D) F = 13.43N

Explanation:

We are given;

Mass if each sphere = 1.65kg

Radius of the first sphere; r1 = 0.206m

Radius of second sphere; r2 = 0.804m

A) initial angular speed of smaller sphere; ω_i = 0 rad/s

Final angular speed of smaller sphere; ω_f = 367 rad/s

Time;t = 14.5 s

The constant angular acceleration is calculated from;

ω_f = ω_i + αt

367 = 0 + α(14.5)

Thus,

α = 367/14.5 = 25.31 rad/s²

The torque is given by the formula;

τ = Iα

Where τ is torque ; I is moment of inertia given as (2/5)Mr²

α is angular acceleration

Thus;

τ = (2/5)(1.65)(0.206)² x 25.31

τ = 0.709 N.m

B) The magnitude of the force that must be applied to give the torque τ is gotten from the formula;

τ = F•r•sin90°

0.709 = F x 0.206 x 1

F = 0.709/0.206

F = 3.44 N

C) Now for the larger sphere, we'll repeat the same procedure in a above. Thus;

The torque is given by the formula;

τ = Iα

Where τ is torque ; I is moment of inertia given as (2/5)Mr²

α is angular acceleration

Thus;

τ = (2/5)(1.65)(0.804)² x 25.31

τ = 10.8 N.m

D) Now for the larger sphere, we'll repeat the same procedure in b above. Thus, τ is gotten from the formula;

τ = F•r•sin90°

10.8 = F x 0.804 x 1

F = 10.8/0.804

F = 13.43N

6 0

3 years ago