All categories

2 years ago

How does the heat from sun reach earth

Physics

1 answer:

kakasveta [241]2 years ago

3 0

Answer:

The sun heats the earth through radiation. Since there is no medium (like the gas in our atmosphere) in space, radiation is the primary way that heat travels in space. When the heat reaches the earth it warms the molecules of the atmosphere, and they warm other molecules and so on.

You might be interested in

Have the rest of my points ( 100 points)<br> SAY SOMETHING NICE DOWN BELOW AND FREE BRAINLEIST

Mashcka [7]

Answer:

Explanation:

hi how was your day?

stay safe hope you have a good day

6 0

2 years ago

Read 2 more answers

When a potential difference of 154 V is applied to the plates of a parallel-plate capacitor, the plates carry a surface charge d

tester [92]

Answer:

$4.7\mu m$

Explanation:

We are given that

Potential difference=V=154 V

Surface charge density= $\sigma=29nC/m^2=29\times 10^{-5} C/m^2$

Using $1 nC/cm^2=10^{-5} C/m^2$

We know that

$C=\frac{\epsilon_0A}{d}=\frac{Q}{V}=\frac{\sigma A}{V}$

$d=\frac{\epsilon_0V}{\sigma}$

Where

$\epsilon_0=8.85\times 10^{-12}C^2/Nm^2$

Using the formula

$d=\frac{8.85\times 10^{-12}\times 154}{29\times 10^{-5}}$

$d=4.7\times 10^{-6} m=4.7\mu m$

Using $1\mu m=10^{-6} m$

Hence, the spacing between the plates= $4.7\mu m$

3 0

2 years ago

What is the length of an aluminum rod at 65Â°C if its length at 15Â°C is 1.2 meters? A. 0.00180 meter B. 1.201386 meters C. 1.2

Deffense [45]

Answer:

Option B is the correct answer.

Explanation:

Thermal expansion

$\Delta L=L\alpha \Delta T$

L = 1.2 meter

ΔT = 65 - 15 = 50°C

Thermal Expansion Coefficient for aluminum, α = 24 x 10⁻⁶/°C

We have change in length

$\Delta L=L\alpha \Delta T=1.2\times 24\times 10^{-6}\times 50=1.44\times 10^{-3}m$

New length = 1.2 + 1.44 x 10⁻³ = 1.2014 m

Option B is the correct answer.

3 0

3 years ago

Read 2 more answers

Assuming no air resistance, how far will a 0.0010 kg raindrop have fallen when it hits the ground 30.0 s later. Assume g = 9.8 m

Serga [27]

D = (1/2)·at²
where d is the distance fallen, a is the acceleration (g in this problem), and t is the time
d = (1/2)·(9.8 m/s²)·(30 s)² = (1/2)·(9.8)·(900) m
d = 4410 m
The answer is b) 4410 m

Note: the mass of the raindrop is irrelevant since the acceleration due to gravity is independent of mass. (Galileo's Leaning Tower of Pisa experiment)

6 0

3 years ago

Read 2 more answers

You perform the Hooke's Law experiment and create a plot of Displacement vs. Force. You add a linear fit and find the following

balandron [24]

Answer: 0.192 N/m

Explanation:

Well, generally when a Hooke's Law experiment is performed the plot is in fact Force vs Displacement, being the Force (in units of Newtons) in the Y-axis and the Displacement (in units of meters) in the X-axis.

In addition, if we add a linear fit the resultant equation will be the Line equation of the form:

$Y=mX+b$

Where $m=\frac{Y_{2}-Y_{1}}{X_{2}-X_{1}}$ is the slope and $b$ is the point where the line intersects the Y-axis.

So, if the equation is:

$Y=0.192X+0.011$

The slope of this line is $0.192 N/m$ which is also the spring constant $k$ .

7 0

3 years ago