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4 years ago

Contrast the nucleus and electron in a cloud

1 answer:

kondor19780726 [428]4 years ago

5 0

The nucleus is the center of the atom made up of protons and neutrons with an overall positive charge. this is where the majority of the atom's mass is.

the electron cloud is the energy levels filled with electrons orbiting the nucleus, there is hardly any mass and it has an overall negative charge equal to that of the nucleus it is orbiting if it is part of a neutral atom.

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Calcula la densidad del hierro , si 393 g ocupan un volumen de 50 ml

eimsori [14]

Density is mass over volume: d=m/v
d = 393/50 => d = 7.86 g/ml

7 0

3 years ago

A small motor uses 200 watts to do 4000 joules of work. How much time this take to occur?

Firdavs [7]

The answer is 20 seconds.

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3 years ago

The index of refraction for silicate flint glass is 1.66 for violet light that has a wavelength in air equal to 400 nm and 1.61

nikitadnepr [17]

Answer:

(a) Angle of incidence for violet is more than the angle of incidence for red

(b) 2.4°

Explanation:

refractive index for violet , v = 1.66

refractive index for red, nR = 1.61

wavelength for violet, λv = 400 nm

wavelength for red, λR = 700 nm

Angle of refraction, r = 30°

(a) Let iv be the angle of incidence for violet.

Use Snell,s law

nv = Sin iv / Sin r

1.66 = Sin iv / Sin 30

Sin iv = 0.83

iv = 56°

Use Snell's law for red

nR = Sin iR / Sin r

where, iR be the angle of incidence for red

1.61 = Sin iR / Sin 30

Sin iR = 0.805

iR = 53.6°

So, the angle of incidence for violet is more than red.

(b) iv - iR = 56° - 53.6° = 2.4°

4 0

3 years ago

A deuteron particle consists of one proton and one neutron and has a mass of 3.34x10^-27 kg. A deuteron particle moving horizont

nikklg [1K]

_dThe radius of curvature of a subatomic particle under a magnetic field is given by the following formula:

$r=\frac{mv}{qB}$

Where:

$\begin{gathered} r=\text{ radius} \\ v=\text{ velocity} \\ q=\text{ charge} \\ B=\text{ magnetic field} \end{gathered}$

We can determine the quotient between the velocity and the charge of the deuteron particle from the formula. First, we divide both sides by the mass:

$\frac{r_d}{m_d}=\frac{v}{q_B_}$

Now, we multiply both sides by the magnetic field "B":

$\frac{Br_d}{m_d}=\frac{v}{q}$

Since the charge of the deuterion is the same as the charge of the proton and the velocity we are considering are the same this means that the quotient between velocity and charge is the same for both particles. Therefore, we can apply the formula for the radius again, this time for the proton:

$r_p=\frac{m_pv}{qB}$

And substitute the quotient between velocity and charge:

$r_p=\frac{m_p}{B}(\frac{Br_d}{m_d})$

Now, we cancel out the magnetic field:

$r_p=\frac{m_pr_d}{m_d}$

Now, we substitute the values:

$r_p=\frac{(1.67\times10^{-27}kg)(0.385m)}{(3.34\times10^{-27}kg)}$

Solving the operations:

$r_p=0.193m=19.3cm$

Therefore, the radius is 19.3 cm.

3 0

2 years ago

What happens to the inertia of an object of its mass is decreased?

Verizon [17]

<span>The inertia of an object increases if the mass is decreased. Inertia is the resistance of any physical object to a change in its state of motion or rest. It is represented numerically by an object's mass.</span>

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4 years ago