The second stone hits the ground exactly one second after the first.
The distance traveled by each stone down the cliff is calculated using second kinematic equation;
where;
- <em>t is the time of motion </em>
- <em /><em> is the initial vertical velocity of the stone = 0</em>
The time taken by the first stone to hit the ground is calculated as;
When compared to the first stone, the time taken by the second stone to hit the ground after 1 second it was released is calculated as
Thus, we can conclude that the second stone hits the ground exactly one second after the first.
"<em>Your question is not complete, it seems be missing the following information;"</em>
A. The second stone hits the ground exactly one second after the first.
B. The second stone hits the ground less than one second after the first
C. The second stone hits the ground more than one second after the first.
D. The second stone hits the ground at the same time as the first.
Learn more here:brainly.com/question/16793944
<span>Good Morning!
A) Beta particles are less energetic than alpha particles.
C) The beta particles are negatively charged;
D) Beta particles move much faster than alpha.
-
B) The beta particles are smaller, so it is that they pass better.
hugs!</span>
Answer: His acceleration is -18.66m/s^2
Explanation:
Ok, the initial speed is 2.8m/s. (we can define the initial direction as the positive direction).
And he wants to stop, so he must accelerate in the opposite direction as the initial movement, then we would have:
a(t) = -A.
So we have a constant, and negative acceleration.
Now, if we want to find the velocity we must integrate over time, and we will get:
v(t) = -A*t + V0
where V0 is the initial velocity, we know that it is 2.8m/s, and t is the time in seconds.
Then the velocity is:
v(t) = -A*t + 2.8m/s.
Now we know that John is brought to rest in 0.15 seconds after he starts slowing down, this means that at t = 0.15 seconds, his velocity is equal to zero.
v(0.15s) = 0m/s = -A*0.15s + 2.8m/s
2.8m/s = A*0.15s
2.8m/s/0.15s = 18.66m/s^2 = A.
So his acceleration is -A, then we have that:
His acceleration is -18.66m/s^2
It helps because it's being transported blah blah whatever the last person said when you first asked this question
Momentum before collision must be equal to momentum after collision
(m1<span> + m</span>2)v = m1v1<span> + m</span>2v<span>2</span>
3.62g*270 m/s=2.30kg* (x)
convert the units to be the same that is convert the kg mass to grams
1kg=1000g
2.30kg=y
230/100*1000=2300g
3.62*270=2300X
977.4g/m/s=2300X
977.4/2300=0.4250M/S
Finding a velocity after the gun is embedded on the block of wood
3.62*270+2300g*0.425=(3.62+2300)*V
977.5+977.5=2303V
1955=2303V
V=1955/2303
V=0.8489M/S