12x+6x^2(3x-2)-8x^2-7x
1 answer:
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Suppose, we are given
two points as
F as (x1, y1)
H as (x2, y2)
assume it divides in m/n
we can use formula
now, we are given points as
F=(x1, y1)=(4,8)
H=(x2, y2)=(10,12)
so,
now, we can find
so, point is
.................Answer
Answer:
7.7 km
Explanation:
Use cosine rule as here given two sides and one angle.
Cosine rule states:
a² = b² + c² - 2bc cos(A)
While solving, treat a = 7.5 km as to that opposite angle is given of 68°
then b = missing side, c = 5.2 km, A = 68°
Applying rule:
7.5² = b² + 5.2² - 2(b)(5.2) cos(68)
56.25 = b² + 27.04 - 3.8959b
56.25 - 27.04 = b² - 3.8959b
b² - 3.8959b = 29.21
b² - 3.8959b - 29.21 = 0
apply quadratic equation, Here [a = 1, b = - 3.8959, c = -29.21]
As length cannot be negative. Hence the value of b is only 7.7 km