<h2>
1080°</h2><h2>
</h2>
basically, the sum of all of the internal angles will be 1080
when you add all interior angles in an octagon you should get 1080
hope that helps !
• So we know that.....
x represent bags of snack and y is bottles of water.
This equations shows the total amount and the cost of each water bottle and snack:
20.00 = 2.50x + 1.00y
Total: $20.00
Snack: $2.50
Water Bottle: $1.00
And this question shows the total items:
11 = x + y
Which there will be some snack + some water bottle = 11 items
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• Now I’m going to first solve for x, which is the amount of bags of snack.
I will use the equation, 11 = x + y.
(First, we’ll subtract y from both side, since we’re solving for x [UNDO])
11 = x + y
-y = - y
_______
11 - y = x —> so x is equal to 11 minus y.
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• Now we’re going to plug the 11 - y as x in the equation: 20.00 = 2.50x + 1.00y to solve for y.
20.00 = 2.50 (11 - y) + 1.00y
20.00 = 27.5 - 2.50y + 1.00y (Distributed)
20.00 = 27.5 - 1.50y (Combine like terms)
20.00 = 27.5 - 1.50y
-27.5 = -27.5 (Subtract -27.5 both side)
——————————
-7.5 = - 1.50y
-7.5 = -1.50y
—— ——— (Divide both side by -1.50)
- 1.50 = -1.50
5 = y
y is equals to 5, which means that there are 5 water bottles.
Now we know there are 11 items total and because there are 5 water bottles, there will be 6 bags of snacks. 11-5=6
—————————————————————
ANSWER:
They bought 6 bags of snacks! :)
Answer:
682
Step-by-step explanation:
620, percentage decreased by - 10% (percent) of its value = 682
Answer:
a) f(x) = x^2
b) f(x) = x
c) any pair of numbers
Step-by-step explanation:
HI!
a)
an example of this kind of function is f(x) = x^2 because
f(x+h) = (x+h)^2 = x^2 + h^2 + 2 xh = f(x) + f(h) + 2xh
teherfore
f(x+h) ≠ f(x) + f(h)
other example is f(x) = x^n with n a whole number different than one
e.g.
f(x)=x^3
f(x+h) = (x+h)^3 = x^3 + h^3 + 3(x^2 h + x h^2) ≠ x^3 + h^3 = f(x) + f(h)
b)
f(x) = x is a function that actually behaves as indicated
f(x+h) = x + h = f(x) + f(h)
others examples of this kind of fucntion are given by multiplying x by any number:
f(x) = ax; f(x+h) = a(x+h) = ax + ah = f(x) + f(h)
c)
Any pair of numbers will make f(x+h) = f(x) + f(h), as mentioned in the previous section
lest consider 10 and 5
f(10+5) = 2 *(10+5) = 2*15 = 30
f(10) = 2*10 = 20
f(5) = 2*5 = 10
f(10) + f(5) = 20+10 = 30 = f(10+5)
