Answer:
-200 metre is less 450m because - 200 metre is negative.
Absolute Value
Absolute Value
means ...
... only how far a number is from zero:
<span>
<span><span>
</span>
<span>
<span>
"6" is 6 away from zero,
and "−6" is also 6 away from zero.
So the absolute value of 6 is 6,
and the absolute value of −6 is also 6 </span>
</span>
</span></span>
More Examples:
<span><span>The absolute value of −9 is 9</span><span>The absolute value of 3 is 3</span><span>The absolute value of 0 is 0</span><span>The absolute value of −156 is 156</span></span>
No Negatives!
So in practice "absolute value" means to remove any negative
sign in front of a number, and to think of all numbers as positive (or
zero).
Absolute Value Symbol
To show that we want the absolute value of something, we put
"|" marks either side (they are called "bars" and are found on the right
side of a keyboard), like these examples:
<span>
<span><span>
|−5| = 5
|7| = 7
</span>
</span></span>
Sometimes absolute value is also written as "abs()", so abs(−1) = 1 is the same as <span>|−1| = 1</span>
Answer: f(4) = 21
Step-by-step explanation:
2(4)^2-11
4^2 = 16
2(16)-11
Multiply 2 and 16
32 - 11
Subtract
21
Answer:
Step-by-step explanation:
To find the inverse of a function you take it in y=f(x) form, switch x and y and then solve for the new y.
So I'll do the first one.
f(x) = 8x-10
y=8x-10 Now switch x and y
x = 8y-10 Now solve for y.
x+10=8y
(x+10)/8 = y
g(x) is not that, so it is not the inverse. Can you figure out the second one?
Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
__
We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
