Answer:
The answer to the question is
The solution contains 4.73 % by mass of NaCl
Explanation:
To solve this we list out the variables thus
The Molarity of NaCl = 0.850 M,
Density of solution = 1.05 g/mL
Molar mass of NaCl = 58.44 g/mol
Therefore mass of NaCl in he solution = (58.44 g/mol) × (0.850 M) = 49.674 g of NaCl
However the density = 1.05 g/mL or 1050 g/L
Therefore the mass percent of NaCl in 1 liter of solution or 1050 g of solution = (49.674/1050) × 100 = 4.73 %
The concentration of NaCl in mass percent = 4.73 %
Answer:
single replacement
Explanation:
it's when one element starts out by itself, then replaces another element in a compound, kicking it out
Answer: 684.4g
Explanation:Please see attachment for explanation
Answer: Carbon-12 and Carbon-14 both have the atomic number of 6.
Explanation: They are both isotopes of one another. This means they have different amount of neutrons, resulting in different atomic masses.
Explanation:
According to Clausius-Claperyon equation,
![ln (\frac{P_{2}}{P_{1}}) = \frac{-\text{heat of vaporization}}{R} \times [\frac{1}{T_{2}} - \frac{1}{T_{1}}]](https://tex.z-dn.net/?f=ln%20%28%5Cfrac%7BP_%7B2%7D%7D%7BP_%7B1%7D%7D%29%20%3D%20%5Cfrac%7B-%5Ctext%7Bheat%20of%20vaporization%7D%7D%7BR%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7BT_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7BT_%7B1%7D%7D%5D)
The given data is as follows.
= (63.5 + 273) K
= 336.6 K
= (78 + 273) K
= 351 K
= 1 atm, 
= ?
Putting the given values into the above equation as follows.
![ln (\frac{1.75 atm}{1 atm}) = \frac{-\text{heat of vaporization}}{8.314 J/mol K} \times [\frac{1}{351 K} - \frac{1}{336.6 K}]](https://tex.z-dn.net/?f=ln%20%28%5Cfrac%7B1.75%20atm%7D%7B1%20atm%7D%29%20%3D%20%5Cfrac%7B-%5Ctext%7Bheat%20of%20vaporization%7D%7D%7B8.314%20J%2Fmol%20K%7D%20%5Ctimes%20%5B%5Cfrac%7B1%7D%7B351%20K%7D%20-%20%5Cfrac%7B1%7D%7B336.6%20K%7D%5D)
= 
= 
= 3813.1 J/mol
Thus, we can conclude that the heat of vaporization of ethanol is 3813.1 J/mol.
