Answer:
Your answer will be B
Step-by-step explanation:
Because you find the difference between 14 and 22 or the difference between 22 and 30 or the difference between 30 and 38. and so on then it will be 8
You then say ok 8 times x so for example 8×1 = 8 then you say ok 22 - 8= 22. So it will be 8x+14...
I hope this helped if not tell me please....❤
Answer:
B
Step-by-step explanation:
First label the equations.
6x +3y= 18 -----(1)
y= -2x +5 -----(2)
subst. (2) into (1):
6x +3(-2x +5)= 18
6x +3(-2x) +3(5)= 18 (expand)
6x -6x +15= 18
15= 18 (simplify)
(reject)
There is no solution.
<u>Further explanation</u><u>:</u>
If I rewrite the first equation into the form of y=mx+c, I would get
6x +3y=18
3y= 18 -6x (bring y term to one side)
y= 6- 2x (÷3 throughout)
y= -2x +6
Notice that the gradients of both lines are equal ( -2). This implies that they are parallel to each other and will never meet. Hence there are no solutions.
Write the left side of the given expression as N/D, where
N = sinA - sin3A + sin5A - sin7A
D = cosA - cos3A - cos5A + cos7A
Therefore we want to show that N/D = cot2A.
We shall use these identities:
sin x - sin y = 2cos((x+y)/2)*sin((x-y)/2)
cos x - cos y = -2sin((x+y)/2)*sin((x-y)2)
N = -(sin7A - sinA) + sin5A - sin3A
= -2cos4A*sin3A + 2cos4A*sinA
= 2cos4A(sinA - sin3A)
= 2cos4A*2cos(2A)sin(-A)
= -4cos4A*cos2A*sinA
D = cos7A + cosA - (cos5A + cos3A)
= 2cos4A*cos3A - 2cos4A*cosA
= 2cos4A(cos3A - cosA)
= 2cos4A*(-2)sin2A*sinA
= -4cos4A*sin2A*sinA
Therefore
N/D = [-4cos4A*cos2A*sinA]/[-4cos4A*sin2A*sinA]
= cos2A/sin2A
= cot2A
This verifies the identity.
14/4
Multiply the denominator and the whole number - 4*3=12
Add the numerator - 12+2=14
Put the answer over the denominator 14/4
