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makvit [3.9K]
2 years ago
11

"What is the scale factor of the following if YZG is dilated to RBP?"​

Mathematics
1 answer:
Nataly [62]2 years ago
5 0

Answer:

1/2

Step-by-step explanation:

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An irrational number written in
Arlecino [84]

Answer:

B. repeating

Step-by-step explanation:

An irrational number written in  decimal form will be nonterminating  and non-repeating  decimals.

For example we have √2 = 1.4142

This rational number is non-terminating and non-repeating.

4 0
3 years ago
Can somebody HELP me as soon as possible.
Butoxors [25]

Answer:

A: Linear

B: Nonlinear

C: Linear

4 0
2 years ago
Read 2 more answers
Consider the following confidence interval interpretation: We are 98% confident that the true mean laptop screen size is between
GalinKa [24]

Answer:

Incorrect

Step-by-step explanation:

This interpretation is incorrect because it states that 98% of the data is with in the confidence interval.

or 98% of the laptop have screen size between 19.2 and 21.4 inches

However, the interpretation would have been correct if it would have stated as - Value of the population mean i.e mean size of the laptop screen lies within the confidence interval.

7 0
3 years ago
You and your friend play a video game. You have a final score of 40 points, and your friend has a final score of -21 points. by
Serhud [2]

Answer:40+(-21)= 19

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A person purchased a slot machine and tested it by playing it 1,137 times. There are 10 different categories of outcomes, includ
ivann1987 [24]

Answer:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

Step-by-step explanation:

A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.

p_v represent the p value for the test

O= obserbed values

E= expected values

The system of hypothesis for this case are:

Null hypothesis: O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

On this case after calculate the statistic they got: \chi^2 = 11.517

And in order to calculate the p value we need to find first the degrees of freedom given by:

df=n-1=10-1=9, where k represent the number of levels (on this cas we have 10 categories)

And in order to calculate the p value we need to calculate the following probability:

p_v= P(\chi^2_{9}>11.517)=0.2419

And on this case if we see the significance level given \alpha=0.1 we see that p_v>alpha so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.

6 0
3 years ago
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