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dmitriy555 [2]
3 years ago
14

Trigonometry you have 10 liters of a juice blend that is 60% juice. suppose that you have added 15 liters of juice to the origin

al 10 liters. what is the percentage of juice in this blend?
Mathematics
1 answer:
ira [324]3 years ago
6 0
Kfc and watermelon is the answer
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If a+b = -0.5 and ab = -2 , then what is 4a^3+9b?
m_a_m_a [10]

Answer:

pls be more cleare

Step-by-step explanation:

type the question properly and clearly

5 0
2 years ago
Subtract the following. Write your answer in standard notation . 18-9.2×10^-4
puteri [66]

Answer:1.799908×10^1

Step-by-step explanation:

18-0.00092

=17.99908

In standard form=1.799908×10^1

8 0
2 years ago
explain how you could use the greatest common factor of 8 and 20 in the distributive property to write 8 + 20 as a product​
GenaCL600 [577]

Answer: 4(5+2) or 4(2+5)

Step-by-step explanation:

8 = 2*2*2

20 = 2*2*5

4(5+2) = 20+8

6 0
2 years ago
We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.
Juli2301 [7.4K]

Answer:

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

Null hypothesis:p\geq 0.8  

Alternative hypothesis:p < 0.8  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation  

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

\hat p=\frac{97}{110}=0.882 estimated proportion of students who completed the modules before class

p_o=0.8 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v{/tex} represent the p value (variable of interest)  2) Concepts and formulas to use  We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%:  Null hypothesis:[tex]p\geq 0.8  

Alternative hypothesis:p < 0.8  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis:p\leq 0.8  

Alternative hypothesis:p > 0.8

p_v =P(Z>2.124)=0.013  

So the p value obtained was a very low value and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis.

5 0
3 years ago
Please help!
Aloiza [94]

Answer:

4 \sin( \frac{2}{7}x )  + 1

Step-by-step explanation:

Let use the basic function of sin first.

Since the midline is 1 and the max point is 5, the amplitude is 4.

The midline is 1 since the midline is at 0,1.

Since we know the distance of the max and midline x values

We can multiply that by 4 to find our period.

\frac{7\pi}{4}    \times 4 = 7\pi

Use the equation 2pi/b to find the b we would use in our equation.

\frac{2\pi}{b}  = 7\pi

The answer is

\frac{2}{7}

so our equation is

4 \sin( \frac{2}{7}x )   + 1

3 0
2 years ago
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