To calculate the number of molecules ch3cooh in a given amount of vinegar, we first need to determine the amount of ch3cooh in the solution by multiplying the percent <span>ch3cooh with the sample amount. Then, convert g to moles and use avogadro's number. We do as follows:
41.9 g vinegar solution ( .05 g </span><span>ch3cooh / g vinegar solution ) (1 mol / 60.05 g ) ( 6.022x10^23 g / 1 mol ) = 2.1x10^22 molecules </span><span>ch3cooh</span>
Answer:
200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water.
Explanation:
The solution is the result of the mixture between the solute, which is the substance that dissolves, and the solvent, which is the substance in which a solute dissolves. That is, a solution (or solution) is a mixture of two or more components, perfectly homogeneous since each component is intimately mixed with the other.
The concentration of solutions is the amount of solute contained in a given amount of solvent or solution. A unit of concentration is the percent weight to volume.
The percent weight to volume is the percentage ratio between the weight of the solute and the volume of the solution. It is calculated as:

Mass is measured in grams, while volume is measured in mL.
In this case:
- Percent weight to volume= 6%
- mass of solute= 12 g
- volue of solution= ?
Replacing:

Solving:
volume of solution*6= 12 g*100

volume of solution= 200 mL
<u><em>200 mL of water is needed to make up a 6.00% (m/v) solution of copper (II) sulphate when 12.0 g of it will be added to water</em></u>
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Answer:
breaking glass
Explanation:
breaking glass cant be reversed
break down food into smaller molecules the body can use; absorb molecules into blood and carry them throughout the body; eliminate wastes from the body
The standard cup of coffee sold in coffee shops have a serving size of 6 ounces. Since there are 28.3495 g in 1 oz, that is equivalent to 170.097 grams. Since you drink two servings, the total mass is 170.097×2 = 340.194 g. Using the molar mass (194.19 g/mol) and the Avogadro's number (6.022×10²³ molecules/mol):
340.194 g caffeine(1 mol/194.19 g)(6.022×10²³ molecules/mol) = <em>1.055×10²⁴ molecules</em>